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Travka [436]
3 years ago
9

A certain wave has a wavelength of 35 meters and a frequency of 4.0 Hz. What is the speed of the wave?

Chemistry
2 answers:
netineya [11]3 years ago
6 0

Answer:

The correct answer is option D.

Explanation:

Wavelength of the wave = \lambda =35 m

Frequency of the wave = f = 4.0 Hz

Time taken by the wave = T

T=\frac{1}{frequency}=\frac{1}{4.0 Hz}=0.25 s

Speed of the wave:

Speed=\frac{35 m}{0.25 s}=140 m/s

Hence, the correct answer is option D.

stepan [7]3 years ago
4 0
Speed of a wave is the wavelength * frequency

speed = 35 * 4 = 140 m/s
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Mixtures of benzene and cyclohexane exhibit ideal behavior. A solution was created containing 1.5 moles of liquid benzene and 2.
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Answer:

Vapour pressure of cyclohexane at 50°C is 490torr

Vapour pressure of benzene at 50°C is 90torr

Explanation:

Using Raoult's law, pressure of a solution is defined by the sum of the product sbetween mole fraction of both solvents and pressure of pure solvents.

P_{solution} = X_{A}P^0_{A}+X_{B}P^0_{B}

In the first solution:

X_{cyclohexane}=\frac{2.5mol}{2.5mol+1.5mol} =0.625

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340torr = 0.625P^0_{A}+0.375P^0_{B} <em>(1)</em>

For the second equation:

X_{cyclohexane}=\frac{3.5mol}{3.5mol+1.5mol} =0.700

X_{benzene}=\frac{1.5mol}{3.5mol+1.5mol} =0.300

370torr = 0.700P^0_{A}+0.300P^0_{B}<em>(2)</em>

Replacing (2) in (1):

340torr = 0.625P^0_{A}+0.375(1233.3-2.333P^0_{A})

340torr = 0.625P^0_{A}+462.5-0.875P^0_{A}

-122.5torr = -0.250P°A

P^0_{A} = 490 torr

<em>Vapour pressure of cyclohexane at 50°C is 490torr</em>

And for benzene:

370torr = 0.700*490torr+0.300P^0_{B}

P^0_{B}=90torr

<em>Vapour pressure of benzene at 50°C is 90torr</em>

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