Question

Juan made 13 out of 20 free throws. If Botina shoots 25 free thows, what's the minimum number she has to make in order to have a better free-throw percentage than Juan?​

Answer 1

Answer:

the answer is 17

Step-by-step explanation:

juans free throw % is 65 so botina has to make 17 out of 25 to get a better percent which is 68

Answer 2

ANSWER:  

Botina has to make 17 successful attempts out of 25 attempts.

SOLUTION:

Given, Juan made 13 out of 20 free throws.

Botina shoots 25 free throws,  

We need find what's the minimum number she has to make in order to have a better free-throw percentage than Juan?

Let, the minimum number of successful throws be x.

Now, percentage of Botina should be greater than percentage of jaun

Percentage of Botina > percentage of Jaun

$\begin{array}{l}{\frac{\text {number of successful attempts by botina}}{\text {total number of attempts by botina}} \times} {100>\frac{\text {number of successful atempts by jaun}}{\text {total number of attempts by jaun}} \times 100}\end{array}$

$\begin{array}{l}{\frac{x}{25} \times 100>\frac{13}{20} \times 100} \\\\ {\frac{x}{25}>\frac{13}{20}} \\\\ {x>25 \times \frac{13}{20}} \\\\ {x>5 \times \frac{13}{4}} \\\\ {x>\frac{65}{4}} \\\\ {x>16.25}\end{array}$

As the number of attempts cannot be in decimal values, we have to consider the integer above 16.25 i.e. 17

Hence, botina has to make 17 successful attempts.