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blsea [12.9K]
4 years ago
14

A canoe displaces 100 L of water. Water weighs 9.8 N/L. What is the buoyant force on the canoe?

Chemistry
2 answers:
Setler79 [48]4 years ago
5 0

Hey there!


The Buoyant force is going to be equal to the weight of the water displaced and it would be like this 100 L(9.8 N/L) = 980 N.



Hope this helped and mind marking me brainliest. Thank you!

Alex4 years ago
5 0
<h3>This answer would be 100L(9.8N/L) = 980N. Really hope this helps you on your problem. Good luck!!!!</h3>
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The time required to reduce the concentration from 0.00757 M to 0.00180 M is equal to 1.52 × 10⁻⁴ s. The half-life period of the reaction is 9.98× 10⁻⁵s.

<h3>What is the rate of reaction?</h3>

The rate of reaction is described as the speed at which reactants are converted into products. A catalyst increases the rate of the reaction without going under any change in the chemical reaction.

Given the initial concentration of the reactant, C₀= 0.00757 M

The concentration of reactant after time t is C₁= 0.00180 M

The rate constant of the reaction, k = 37.9 M⁻¹s⁻¹

For the first-order reaction: C_t =C_0-kt

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t =  1.52 × 10⁻⁴ s

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t_{\frac{1}{2} } =\frac{0.00757}{2\times 37.9}

Half-life of the reaction = 9.98 × 10⁻⁵s

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