Answer:
Explanation:
NaNO₃ = Na⁺ + NO₃⁻¹
.497 M .497 M
moles of NO₃⁻¹ = .897 x .497 = .4458 moles
Ca( NO₃)₂ = Ca + 2 NO₃⁻¹
.341 M 2 x .341 M = .682 M
moles of NO₃⁻¹ = .813 x .682 = .5544 moles
Total moles = .4458 moles + .5544 moles
= 1.0002 moles
volume of solution = 897 + 813 = 1710 mL
= 1.710 L
concentration of nitrate ion = 1.0002 / 1.710 M
= .585 M
Answer: We take 20 ml of 1.0 M fruit drink and add 80 ml of water to get 100 ml of 0.2 M solution.
Explanation:
According to the neutralization law,
where,
= molarity of stock solution = 0.2 M
= volume of stock solution = 100 ml
= molarity of resulting solution = 1.0 M
= volume of resulting solution = ?
Now put all the given values in the above law, we get the volume of resulting solution.
Therefore, the volume of 1.0 M required is 20 ml.
We take 20 ml of 1.0 M fruit drink and add 80 ml of water to get 100 ml of 0.2 M solution.
B. A gram would have a lot more molecules of propane than a mole
I pretty sure it is Gas. Hope this is what you're looking for. Have a great day! :D
