Answer:
We have to add 9.82 grams of calcium acetate
Explanation:
Step 1: Data given
Molarity of the calcium acetate solution = 0.207 M
Volume = 300 mL = 0.300 L
Molar mass calcium acetate = 158.17 g/mol
Step 2: Calculate moles calcium acetate
Moles calcium acetate = molarity * volume
Moles calcium acetate = 0.207 M * 0.300 L
Moles calcium acetate = 0.0621 moles
Step 3: Calculate mass calcium acetate
Mass calcium acetate = moles * molar mass
Mass calcium acetate = 0.0621 moles * 158.17 g/mol
Mass calcium acetate = 9.82 grams
We have to add 9.82 grams of calcium acetate
The reactants are oxygen and nitrogen monoxide.
<h3>What is nitrogen monoxide?</h3>
Nitrogen oxide, also known as nitrogen monoxide or nitric oxide, is an inert gas with the chemical formula NO. It is one of the main nitrogen oxides. Free radical nitric oxide (•N=O or •NO) possesses an unpaired electron, which is commonly indicated by a dot in its chemical formula. As a heteronuclear diatomic molecule, nitric oxide also contributed to the development of early modern theories of chemical bonding.
Nitric oxide is a chemical compound that occurs in combustion systems and can be produced by lightning during thunderstorms. It is a crucial intermediate in industrial chemistry. In many physiological and pathological processes in animals, including humans, nitric oxide serves as a signaling molecule.
To learn more about nitrogen monoxide from the given link:
brainly.com/question/13428103
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The answer is D. Gold. Malleability, the ability for a material to be hammered or shaped into thin sheets, is a common property of metals. Among the choices, gold is the only metal. Also, gold is considered to be the most malleable metal.
Answer:
In neutralization reaction water and a salt is produced.
The answer is: 27 grams of aluminium.
Balanced chemical reaction: 2Al + 3H₂SO₄ → Al₂(SO₄)₃ + 3H₂.
n(H₂) = 1.5 mol; amount of hydrogen.
Form chemical reaction: n(Al) : n(H₂) = 2 : 3.
n(Al) = 2 · 1.5 mol ÷ 3.
n(Al) = 1.0 mol; amount of aluminium.
m(Al) = n(Al) · M(Al).
m(Al) = 1 mol · 27 g/mol.
m(Al) = 27 g; mass of aluminium.
