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SashulF [63]
3 years ago
10

what is the total displacement of a dog that runs north 80 meters to chase a ball, returns to its master, and runs south 20 mete

rs
Chemistry
1 answer:
vladimir1956 [14]3 years ago
7 0
The total displacement will be 20 meters.
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When 500 g of water is cooled from 80.0°C to 10.0°C, how much heat energy is lost?
vampirchik [111]

I don’t know

Explanation:

6 0
3 years ago
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The percent by mass of copper in CuBr2 is Use mc004-1.jpg. 28.45%. 44.30%. 63.55%. 71.55%.
Greeley [361]
First, we must find the total mass of CuBr₂:
Mass = 64 + 2 x 80
Mass = 224

Percentage mass of copper = mass of copper x 100 / total mass
Percentage mass of copper = (64 / 224) x 100
Percentage mass of copper = 28.45%
3 0
3 years ago
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Cryogenics has the potential to be useful in a variety of fields, including medicine. Suppose you have engineered a method to su
tatiyna

Explanation:

It is known that the specific heat capacity of Liver (C_{p}) is 3.59 kJ kg^{-1}.K^{-1}

It is given that :

Initial temperature of Liver = Body temperature = 37^{o}C = 310 K

Final temperature of Liver = 180 K

Relation between heat energy, mass, and change in temperature is as follows.

                        Q = m \times C_{p} \times \Delta T

Now, putting the given values into the above formula as follows.

                    Q = m \times C_{p} \times \Delta T

                    Q = 1.5 kg \times 3.59 kJ/kg.K \times (310 - 180) K

                         =  700.05 kJ

Therefore, we can conclude that amount of heat which must be removed from the liver is 700.05 kJ.

7 0
3 years ago
Li + HNO3 > LiNO3 + H2 how do I balance it? Show work pls
azamat

Answer: The balanced equation is 2Li + 2HNO_{3} \rightarrow 2LiNO_{3} + H_{2}.

Explanation:

The given reaction equation is as follows.

Li + HNO_{3} \rightarrow LiNO_{3} + H_{2}

Number of atoms present on reactant side are as follows.

  • Li = 1
  • H = 1
  • NO_{3} = 1

Number of atoms present on product side are as follows.

  • Li = 1
  • H = 2
  • NO_{3} = 1

To balance this equation, multiply Li by 2 and HNO_{3} by 2 on reactant side. Also, multiply LiNO_{3} by 2 on product side.

Hence, the equation can be rewritten as follows.

2Li + 2HNO_{3} \rightarrow 2LiNO_{3} + H_{2}

Now, number of atoms present on reactant side are as follows.

  • Li = 2
  • H = 2
  • NO_{3} = 2

Number of atoms present on product side are as follows.

  • Li = 2
  • H = 2
  • NO_{3} = 2

As there are same number of atoms on both reactant and product side. Hence, the equation is now balanced.

Thus, we can conclude that the balanced equation is 2Li + 2HNO_{3} \rightarrow 2LiNO_{3} + H_{2}.

3 0
2 years ago
If you had a 0.800 L solution containing 0.0240 M of Fe3+(aq), and you wished to add enough 1.38 M NaOH(aq) to precipitate all o
guapka [62]

Answer:

0.041 L = 41.3 mL

Explanation:

This problem we will solve by considering the stoichiometry of the reaction and the definition of molarity.

Number of moles in .800 L solution:

0.800 L x 0.0240 M = 0.800 L x .0240 mol/L = 0.0192  mol Fe³⁺

to form the precipitate Fe(OH)₃ we will need 3 times .0192

mol NaOH required = 0.057

given the concentration of 1.38 mol M NaOH we can calculate how many milliliters of NaOH will contain 0.057 mol:

1.L/1.38 mol NaOH x 0.057 mol NaOH = 0.041 L

0.041 L x 1000 mL/1L = 41.3 mL

7 0
3 years ago
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