A parachutist's rate during a free fall reaches 198 feet per second. What is this rate in meters per second? At this rate, how m
1 answer:
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Answer:
C) 960
Step-by-step explanation:
Let's expand the factorial.
n! = 1*2*3*4*...n
6! = 1*2*3*4*5*6
3!= 1*2*3
The given expression
=
Canceling out the common terms, we get
=
= 8.4.5.6 [here . represents multiplication]
= 960
Answer: C) 960
Thank you.
Answer:
( About ) 1,099 pounds
Step-by-step explanation:
The force required to keep this truck from rolling down the hill is opposed by the force of friction, comparative to the 2600 pounds of force against this friction. It should be that this opposing force is at work more towards the bottom of this hill, and thus the question asks the magnitude of latter force to keep this truck idle -
|| F || = sin( 25 ) * ( Fg ) = sin( 25 ) * ( 2600 lb ) = ( About ) 1098.80748 pounds
<u><em>This can be rounded to a solution of 1099 pounds</em></u>
