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Zielflug [23.3K]
3 years ago
12

4. Evaluate the geometric series given a1 = 4, r = -2 and n = 12

Mathematics
1 answer:
katrin2010 [14]3 years ago
3 0

we know that

a1=7

r=2

n=14

then

Sn=a1*[(r^n)-1]/(r-1)-------------->S14= 7*[(2^14)-1]/(2-1)=114681

the answer is 114681

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What is the equation of the inverse function A(n)=3n-20
Allisa [31]

Answer:

A^{-1}(n)=\frac{1}{3}n+\frac{20}{3}

Step-by-step explanation:

First, let's change those variables to x and y, just for the sake of convenience.  In order to find the inverse of a function algebraically, switch the x and y coordinates, then solve for the new y.  Letting y = A(n) and x = n (we will switch them back when we're done):

y = 3x - 20.  This is linear; a line with a slope of 3 and a y-intercept of -20.  When we switch the x and the y, we get:

x = 3y - 20.  Now we solve for the new y.  Begin by adding 20 to both sides:

x + 20 = 3y.  Now divide both sides by 3:

\frac{x+20}{3}=y, or to write it in slope-intercept form, like the function you started with:

y=\frac{1}{3}x+\frac{20}{3}

This is also a line, with a slope of 1/3 and a y-intercept of +20/3

Now, replacing:

A^{-1}(n)=\frac{1}{3}n+\frac{20}{3}

That is how to write the inverse using function notation.  The little -1 as an exponent tells us that this is the inverse of the function A(n).

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4 years ago
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Answer:

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Step-by-step explanation:

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3 years ago
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Manny, Levi, and Drew have coin collections. Manny has as many coins as Levi has. Drew has as many coins as Manny.
aev [14]
The answer is A because all three of them have the same amount of coins

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3 years ago
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A man can drive a motorboat 70 miles down the Colorado River in the same amount of time that he can drive 40 miles upstream. Fin
pochemuha

The speed of the current is 40.34 mph approximately.

<u>SOLUTION: </u>

Given, a man can drive a motorboat 70 miles down the Colorado River in the same amount of time that he can drive 40 miles upstream.  

We have to find the speed of the current if the speed of the boat is 11 mph in still water. Now, let the speed of river be a mph.  Then, speed of boat in upstream will be a-11 mph and speed in downstream will be a+11 mph.

And, we know that, \text{ distance } =\text{ speed }\times \text{ time }

\begin{array}{l}{\text { So, for upstream } \rightarrow 40=(a-11) \times \text { time taken } \rightarrow \text { time taken }=\frac{40}{a-11}} \\\\ {\text { And for downstream } \rightarrow 70=(a+11) \times \text { time taken } \rightarrow \text { time taken }=\frac{70}{a+11}}\end{array}

We are given that, time taken for both are same. So \frac{40}{a-11}=\frac{70}{a+11}

\begin{array}{l}{\rightarrow 40(a+11)=70(a-11)} \\\\ {\rightarrow 40 a+440=70 a-770} \\\\ {\rightarrow 70 a-40 a=770+440} \\\\ {\rightarrow 30 a=1210} \\\\ {\rightarrow a=40.33}\end{array}

8 0
3 years ago
12x5 – 10x2 + x – 45
qaws [65]
(a)
12x  ^{5}    - 10x ^{2}  + x - 45
(b)we have 4 terms in this expression.
(c)+12 is the leading coefficient in
12x ^{5}

(d) constant is -45
6 0
3 years ago
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