Jose burns an average of 200 calories in 25 minutes of running. How many calories does Jose burn per minute?

A transformation doubles each point's x-coordinate and leaves the point's y-coordinate intact. What will the transformation have

g100num [7]

It shouldn’t be any longer vertically so that should be your answer

7 0

3 years ago

Determine whether the conjecture is true or false. Give a counterexample for any false conjecture. Given: Point B is in the inte

Arte-miy333 [17]

True because point B is the interior

5 0

3 years ago

Read 2 more answers

Given that f(x)=6x+2 and g(x)=2x+4/5 solve for g(f(1)) A.1 B.3 C.4 D.8

GrogVix [38]

Answer:

The value of g(f(1)) is 84/5

Step-by-step explanation:

To find the answer to a composite function, start with the function on the inside, which is f(1). So, we input 1 into the f(x) equation and evaluate.

f(x) = 6x + 2

f(1) = 6(1) + 2

f(1) = 6 + 2

f(1) = 8

Now that we have the answer of 8, we can input that in for x in the outside function, which is g(x).

g(x) = 2x + 4/5

g(8) = 2(8) + 4/5

g(8) = 16 + 4/5

g(8) = 84/5

6 0

3 years ago

Given: ABC is a right triangle with right angle C. AC=15 centimeters and m∠A=40∘ . What is BC ? Enter your answer, rounded to th

konstantin123 [22]

In order to answer this question, the figure in the first picture will be helpful to understand what a right triangle is. Here, a right angle refers to $90\°$ .

However, if we want to solve the problem we have to know certain things before:

In the second figure is shown a general right triangle with its three sides and another given angle, we will name it $\alpha$ :

The side opposite to the right angle is called The Hypotenuse (h)

The side opposite to the angle $\alpha$ is called the Opposite (O)

The side next to the angle $\alpha$ is called the Adjacent (A)

So, going back to the triangle of our question (first figure):

The Hypotenuse is AB

The Opposite is BC

The Adjacent is AC

Now, if we want to find the length of each side of a right triangle, we have to use the Pythagorean Theorem and Trigonometric Functions:

Pythagorean Theorem

$h^{2}=A^{2} +O^{2}$ (1)

Trigonometric Functions (here are shown three of them):

Sine: $sin(\alpha)=\frac{O}{h}$ (2)

Cosine: $cos(\alpha)=\frac{A}{h}$ (3)

Tangent: $tan(\alpha)=\frac{O}{A}$ (4)

In this case the function that works for this problem is cosine (3), let’s apply it here:

$cos(40\°)=\frac{AC}{h}$

$cos(40\°)=\frac{15}{h}$ (5)

And we will use the Pythagorean Theorem to find the hypotenuse, as well:

$h^{2}=AC^{2}+BC^{2}$

$h^{2}=15^{2}+BC^{2}$ (6)

$h=\sqrt{225+BC^2}$ (7)

Substitute (7) in (5):

$cos(40\°)=\frac{15}{\sqrt{225+BC^2}}$

Then clear BC, which is the side we want:

${\sqrt{225+BC^2}}=\frac{15}{cos(40\°)}$

${{\sqrt{225+BC^2}}^2={(\frac{15}{cos(40\°)})}^2$

$225+BC^{2}=\frac{225}{{(cos(40\°))}^2}$

$BC^2=\frac{225}{{(cos(40\°))}^2}-225$

$BC=\sqrt{158,41}$

$BC=12.58$

Finally $BC$ is approximately 13 cm

7 0

4 years ago

Read 2 more answers

Five times the sum of the digits of a two-digit number is 13 less than the original number. If you reverse the digits in the two

In-s [12.5K]

Let the original 2-digit number be xy.
Because 5 times the sum of the digits is 13 less than the number, therefore
5(x + y) = 10x + y - 13
5x + 5y = 10x + y - 13
-5x + 4y = - 13 (1)

The number with reversed digits is yx.
Because 4 times the sum of the digits is 21 less than the reversed 2-digit number, therefore
4(x + y) = 10y + x - 21
4x + 4y = 10y + x - 21
3x - 6y = -21
x - 2y = -7
x = 2y - 7 (2)

Substitute (2) into (1).
-5(2y - 7) + 4y = -13
-10y + 35 + 4y = -13
-6y = -48
y = 8

From (3), obtain
x = 2*8 - 7 = 9

Answers:
The original 2-digit number is 98
The reversed 2-digit number is 89
The difference between the original and the reversed 2-digit numbers is
98 - 89 = 9

4 0

3 years ago

Jose burns an average of 200 calories in 25 minutes of running. How many calories does Jose burn per minute?​

Jose burns an average of 200 calories in 25 minutes of running. How many calories does Jose burn per minute?