First, we convert the given radius of the wheel to meters giving us an answre of 0.325 m. Then, we calculate for the circumference. C = 2πrr Substituting, C = 2π(0.325 m) = 2.04 m Then, we have a road that is 40 m long, the number of complete revolutions is, n = 40/2.04 m = 20
