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Brut [27]
3 years ago
14

Add.

Mathematics
2 answers:
maw [93]3 years ago
8 0
120 minute in toya so think
77julia77 [94]3 years ago
3 0
I think the answer would be 120 min 
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If you could help I would appreciate it I
dusya [7]

Answer:

2

Step-by-step explanation:

i used a calculator and the rounded

4 0
2 years ago
Read 2 more answers
6. A factory has two types of machines.
Pie

210 pieces

Step-by-step explanation:

First, you need to figure out how many pieces a single machine can cut in a minute, so you need to divide 105 by 3, which gets you 35 pieces per minute.

Next, since we know there are 6 machines, and one machine canncut 35 pieces per minute, we can the figure out how many pieces all 6 cutting machines can cut in 1 minute. You would do this by making an equation such as this:

35 \times 6 = x

The x represents the total number of pieces cut by all 6 machines in one minute.

Next, since we now have an equation, we can go ahead and solve it. We would multiply 35 by 6, which would get us 210 pieces per minute that can be cut by all six machines

8 0
3 years ago
Read 2 more answers
HELP NOWWWWW PLEASEEEEE<br> How many 1/3's are in 1 and 2/3?
kiruha [24]

Answer:

5 thirds

Step-by-step explanation:

Make 1 2/3 into a improper fraction. Now you have 5/3. 5/3-(1/3*5)=0

Therefore, 5x1/3=5/3=1 2/3

7 0
3 years ago
Read 2 more answers
The function h is defined by h (y) = 2y-7.<br> What is the value of h(8) ?<br> ooo
kozerog [31]

Answer:

The value of h(8) = 9  

Step-by-step explanation:

Given function as

h(y) = 2y - 7

For y = 8

Put the value of y in given function

So, h(8) = 2 (8) - 7

OR , h(8) = 16 - 7

∴  h(8) = 9  

Hence the value of h(8) = 9    Answer

6 0
3 years ago
Divide 6.391 ÷ 0.57. Round the quotient to the nearest hundredth.
Paul [167]
The answer is 11.21, dividing 6.391 by 0.57 will give you 11.2122807018.
Rounding to 11.21 because the thousandths place is less then 5 so the hundredths place stays the same.
               (numeral)~(decimal)~(tenths)(hundredths)(thousandths)
5 0
3 years ago
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