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Verdich [7]
2 years ago
14

Click the button that shows the correct relationship of the electron affinities of the elements sodium and phosphorus.

Chemistry
2 answers:
Akimi4 [234]2 years ago
4 0

Answer:

Phosphorus’ electron affinity value is more negative than the electron affinity value of sodium.

Explanation:

I got it correct

VikaD [51]2 years ago
3 0

Answer:

The second option

Explanation:

I took the quiz and got it correct

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What kind of reaction is this? 2Li + Cl2 —> 2LiCl
Leni [432]

Answer:

synthesis

Explanation:

8 0
2 years ago
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What causes gas particles to collide with the walls of their containers?
blondinia [14]

Answer:

Kinetic energy

Explanation:

The kinetic energy of a particle is directly proportional to the temperature of it. An increase in temperature increases the speed in which the molecules move, causing t[he particles to collide with the walls of their containers.

5 0
3 years ago
Determine the percent water in MgSO4*7H20?
Semmy [17]

Answer:

\% H_2O=51.2\%

Explanation:

Hello!

In this case, since the percent water is computed by dividing the amount of water by the total mass of the hydrate; we infer we first need the molar mass of water and that of the hydrate as shown below:

MM_{MgSO_4* 7H_2O}=120.36 g/mol+7*18.02g/mol\\\\MM_{MgSO_4* 7H_2O}=246.5g/mol

Thus, the percent water is:

\% H_2O=\frac{7*MM_{H_2O}}{MM_{MgSO_4* 7H_2O}} *100\%\\\\

So we plug in to obtain:

\% H_2O=\frac{7*18.02}{246.5} *100\%\\\\\% H_2O=51.2\%

Best regards!

5 0
2 years ago
Is the narrator male or female in the story leaving?​
AlladinOne [14]
The narrator is a female

Hope this helps
8 0
3 years ago
The rate constant for the second-order reaction: 2NOBr(g) → 2NO(g) + Br2(g) is 0.80/(M · s) at 10°C. Starting with a concentrati
a_sh-v [17]

Answer : The concentration of NOBr after 95 s is, 0.013 M

Explanation :

The integrated rate law equation for second order reaction follows:

k=\frac{1}{t}\left (\frac{1}{[A]}-\frac{1}{[A]_o}\right)

where,

k = rate constant = 0.80M^{-1}s^{-1}

t = time taken  = 95 s

[A] = concentration of substance after time 't' = ?

[A]_o = Initial concentration = 0.86 M

Now put all the given values in above equation, we get:

0.80=\frac{1}{95}\left (\frac{1}{[A]}-\frac{1}{(0.86)}\right)

[A] = 0.013 M

Hence, the concentration of NOBr after 95 s is, 0.013 M

4 0
2 years ago
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