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3 years ago

How many electrons fit in the part of the third energy level shown

Chemistry

1 answer:

makkiz [27]3 years ago

5 0

Answer:

18 electrons

Explanation:

Note: The third energy level can actually hold up to 18 electrons, so it is not really filled when it has 8 electrons in it.

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Which two types of chemical reactions do not always occur? What, specifically, do you need to do to see if they occur or not

meriva

Answer:

Molecules must collide with sufficient energy, known as the activation energy, so that chemical bonds can break. Molecules must collide with the proper orientation. A collision that meets these two criteria, and that results in a chemical reaction, is known as a successful collision or an effective collision.

6 0

3 years ago

How much energy was lost in the total process illustrated? Please Help

7nadin3 [17]

Answer:

30%

Explanation:

I don't know how to explain but I learnt this yesterday

8 0

3 years ago

Read 2 more answers

A cubic meter of air was sampled at 1.0 ATM and 40 C.

ladessa [460]

The amount of nitrogen oxide in the air sample is determined as 7.01 ppb.

<h3>Amount of Nitrogen oxide in the air</h3>

The amount of Nitrogen oxide (NO2) in the air in parts per billion (ppb) is calculated as follows;

12 micrograms of NO2 = 12 μg = 12 x 10⁻⁶ g

PV = nRT

V = nRT/P

Where;

V is volume of NO2 gas
n is number of moles of NO2 gas
T is temperature = 40 C = 313 K

n = m/M

M = molar mass of NO2 = 46

n = 12 x 10⁻⁶/46

n = 2.73 x 10⁻⁷ mole

V = (2.73 x 10⁻⁷ x 0.082057 x 313)/(1)

V = 7.01 x 10⁻⁶ L

V = 7.01 x 10⁻⁹ m³

<h3>Amount of NO2 In parts per billion</h3>

= (Volume of NO2)/(volume of air) x 10⁹

= (7.01 x 10⁻⁹)/(1) x 10⁹

= 7.01 ppb

Thus, the amount of nitrogen oxide in the air sample is determined as 7.01 ppb.

Learn more about nitrogen oxide here: brainly.com/question/13629381

#SPJ1

5 0

2 years ago

The mole fraction of a non electrolyte (MM 101.1 g/mol) in an aqueous solution is 0.0194. The solution's density is 1.0627 g/mL.

yanalaym [24]

Answer:

Molarity for the solution is 1.05 mol/L

Explanation:

Mole fraction of solute = 0.0194

Solution's density = 1.0627 g/mL

We must know that sum of mole fraction = 1

Mole fraction of solute + Mole fraction of solvent = 1

0.0194 + Mole fraction of solvent = 1

Mole fraction of solvent = 1 - 0.0194 → 0.9806

Molarity is mol of solute in 1L of solution, so we have to determine solution's volume in L

With molar mass we can determine the mass of solute and solvent and then, the solution's mass

0.0194 mol . 101.1 g/ mol = 1.96 g of non electrolyte solute

0.9806 mol . 18 g/mol = 17.65 g of water

Mass of solution = mass of solute + mass of solvent

1.96 g + 17.65 g = 19.6 g (mass of solution)

Solution's density = Solution's mass / Solution's volume

1.0627 g/mL = 19.6 g / Solution's volume

Solution's volume = 19.6 g / 1.0627 g/mol →18.4 mL

Let's convert the mass from mL to L

18.4mL . 1L / 1000 mL = 0.0184 L

We have the moles of solute, so let's determine molarity

mol/L → 0.0194 mol / 0.0184 L = 1.05 M

8 0

3 years ago

How many molecules are there in 840 grams of na2SO4

beks73 [17]

Answer:

3.56x10^24 molecules

Explanation:

The following data were obtained from the question:

Mass of Na2SO4 = 840g

Molar Mass of Na2SO4 = (23 x2) + 32 + (16x4) =46 + 12 + 64 = 142g/mol

From Avogadro's hypothesis, 1mole of any substance contains 6.02x10^23 molecules. This also gives that 1mole of Na2SO4 contains 6.02x10^23 molecules.

If 1 mole (i.e 142g) contains 6.02x10^23 molecules,

Therefore, 840g of Na2SO4 will contain = (840 x 6.02x10^23)/142 = 3.56x10^24 molecules

4 0

4 years ago