D. MgO + 2HCI – MgCl2 + H20
<h3>Further explanation</h3>
The chemical equation is said to be balanced if the number of atoms in the reactants is equal to the number of atoms in the product
A. CaO2 + HCl → CaCl2 + H20
atoms O, Cl and H are not the same
B. CO2 + H2O + H2CO2
atoms O are not the same
C. K+ H2O → K20 + H2
atoms K are not the same
D. MgO + 2HCI – MgCl2 + H20
Mg, left = 1, right=1
O, left=1, right=1
H, left=2, right=2
Cl, left=2, right=2
Chemical equation is balanced
A small sample of methane burns, releasing 120.0 kJ of heat and doing 830.0 kJ of work. The total energy released is -950.0 kJ.
Energy is a property that is transferred to a physical system, recognizable in the performance of work and in the form of heat and light.
A small sample of methane undergoes combustion. As the hot gas mixture expands, it releases energy (E).
- It releases 120.0 kJ of heat. By convention, when heat is released, we assign it a negative sign. Thus, q = -120.0 kJ.
- It does 830.0 kJ of work. By convention, when the system does work on the surroundings, we assign it a negative sign. Thus, w = -830.0 kJ.
The change in the energy is the sum of the heat released and the work done.
ΔE = q + w = -120.0 kJ + (-830.0 kJ) = -950.0 kJ
A small sample of methane burns, releasing 120.0 kJ of heat and doing 830.0 kJ of work. The total energy released is -950.0 kJ.
Learn more about energy here: brainly.com/question/13881533
Answer:
They were made in unstable conditions
Explanation: Im smarty pants
Explanation:
The given data is as follows.
Magnetic field (B) = 0.30 T
Current (I) = 24 A
n = 
charge on electron (e) =
C
Formula to calculate the potential difference is as follows.
V = 
= 
=
V
Therefore, we can conclude that value of potential difference is
V.
The given question is incomplete. The complete question is:
Suppose a current of 0.920 A is passed through an electroplating cell with an aqueous solution of agno3 in the cathode compartment for 47.0 seconds. Calculate the mass of pure silver deposited on a metal object made into the cathode of the cell.
Answer: 0.0484 g
Explanation:
where Q= quantity of electricity in coloumbs
I = current in amperes = 0.920 A
t= time in seconds = 47.0 sec

96500 Coloumb of electricity electrolyzes 1 mole of Ag
43.24 C of electricity deposits =
of Ag
Thus the mass of pure silver deposited on a metal object made into the cathode of the cell is 0.0484 g