Question

Write expression as a complex number in standard form and show work [(13i)/(1-2i)]

Answer 1

The solution
let A = 13i /1-2i 
    so A = 13i (1+2i) /(1-2i) ( 1+2i) = 13i (1+2i) /1² - (2i)² = 13i -26 / 1  
finally A = 13i -26