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3 years ago

Which equation shows a linear relationship between the variables stated?

1 answer:

8 0

A and B cannot be the answer because they are square equations and not linear. C also is not the answer because you can't make m/a = something

D is the answer because you can divide both sides by I and get equation
V/I=R. Right side is linear therefore that is the answer.

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When modeling hourly pay, which part of the equation is used to represent the<br> hourly rate?

lesantik [10]

Answer:

y = mx + b

Step-by-step explanation:

The reason is, x is always the hour, and m is the amount of money you earn in the hours.

3 0

3 years ago

What’s is the answer

kvasek [131]

When you are multiplying an exponent directly into a number/variable with an exponent, you multiply the exponents together.

For example:

$(x^{2} )^{3} = x^6$

$(x^{3} )^5=x^{15}$

When you are multiplying a variable with an exponent by another variable with an exponent, you add the exponents together.

For example:

$(x^{2} )(x^{3})=x^{5}$

$(x^{1} )(x^{2})=x^{3}$

$(\frac{(x^{-3})(y^{2})}{(x^{4})(y^{6})} )^{3}=\frac{(x^{-9})(y^{6})}{(x^{12})(y^{18})}$

You multiply 3 into each exponent in the numerator and the denominator

$\frac{(x^{-9})(y^{6})}{(x^{12})(y^{18})}= \frac{y^{6}}{(x^{9})(x^{12})(y^{18})}$

When you have a negative exponent, you move it to the other side of the fraction to make the exponent positive.

$\frac{y^{6}}{(x^{21})(y^{18})} = \frac{1}{(x^{21})(y^{12})}$

When you have something like this:

$\frac{x^{2}}{x^5}$

You subtract the exponents together, so:

$\frac{x^2}{x^5} = x^{2-5} = x^{-3} = \frac{1}{x^3}$

Your answer is the second option

3 0

3 years ago

Finding area of shaded sectors.

tekilochka [14]

Answer:

69.81 sq. m. (rounded to 2 decimal places)

Step-by-step explanation:

The sector of a circle is "part" or "portion" of a circle. The formula for the area of a sector is:

$A=\frac{\theta}{360}*\pi r^2$

Where

$\theta$ is the central angle

r is the radius

Given the figure, the arc is given as 80 degrees, but not the central angle of the shaded sector. But from geometry we know that the central angle and the intercepted arc have the same measure. So we can say:

$\theta = 80$