Answer:
Step-by-step explanation:
The worth of a penny is 1 cent = 1/100 = $0.01
The worth of a nickel is 5 cents = 5/100 = $0.05
Let x represent the number of pennies that she could have. Lucy has some pennies and some nickels. She has a maximum of 15 coins. If lucky has 6.999999999999999, it means that
6.999999999999999 + x ≥ 15
x ≥ 15 - 6.999999999999999
x ≥ 8
If the 15 coins worth a minimum of $0.47combined, it means that
0.05(6.999999999999999) + 0.01x ≤ 0.47
0.35 + 0.01x ≤ 0.47
0.01x ≤ 0.47 - 0.35
0.01x ≤ 0.12
x ≤ 0.12/0.01
x ≤ 12
Therefore, the possible values for the number of pennies that she could have is 8 ≤ x ≤ 12
The remainder of the given expression will be 66.
<h3>What is division?</h3>
Division is a method of distributing a group of things into equal parts. It is one of the four basic operations of arithmetic.
The given polynomlal x⁴+3x³-6x²-12x-8 will be divided by x-3 so we need to find the remainder:-
x-3) x⁴+3x³-6x²-12x-8 ( x³-6x²+12x+24
x²-3x³
_______________
6x³-6x²-12x-8
6x³-18x²
________________________
12x²-12x-8
-12x²-36x
_____________________
24x-8
24x-72
_______________________
66
Hence the remainder of the given expression will be 66.
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Answer:
985.15mg
Step-by-step explanation:
Calculation for how many milligrams of the drug should he receive every 12 hours
First step is to calculate the weight in kg
255 lbs = 255/2.2 = 115.9 kg
Second step is multiply mg/kg in order to get total medicine per day
Dose per day=115.9kg × 17 mg
Dose per day= 1,970.3
Third step is to calculate how many milligrams of the drug should he receive by dividing the day dose by 2
Dose milligrams=1,970.3/2
Dose milligrams=985.15mg
Therefore how many milligrams of the drug should he receive every 12 hours will be 985.15mg
Answer:
Step-by-step explanation:
We need to find the LCM of 12 and 9.
<u>Their LCM is:</u>
- LCM(12, 9) = 2*2*3*3 = 36
Number of light fixtures and light bulbs is 36.
<u>Number of packages will be:</u>
- 36/12 = 3 and
- 36/9 = 4 respectively.
Answer:.86
Step-by-step explanation:
Put the given data within the formula for the zscore.
