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Radda [10]
2 years ago
5

Find the value of x for which line L is parallel to M

Mathematics
1 answer:
weqwewe [10]2 years ago
4 0

Answer:

50

Step-by-step explanation:

Angle 95 and ( 2x - 5 ) are alternate interior angles.

Alternate interior angles are equal.

2x - 5 = 95

2x = 95 + 5

2x = 100

x = 100 / 2

x = 50

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Suppose that e and f are two events and that upper p left parenthesis upper e right parenthesis p(e) equals = 0.5 0.5 and upper
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2 years ago
I NEED HELP PLEASEEEEEEEEEEEEEEEEEEEEEEEEE
ser-zykov [4K]

Answer:

58 square feet

Step-by-step explanation:

The room is already broken down into two smaller rectangles.

The smaller of the two measures 4 ft by 2 ft. A=lw, so substitute 4 for l and 2 for w.

A(smaller rectangle) =(4)(2), or (4*2).

A(smaller rectangle) =8

The larger measures 10 ft by 5 ft, so using the same method, multiply l times w.

A(larger rectangle) =(10)(5), or (10*5).

A(larger rectangle) =50

Add the two rectangles' areas together to find the total area of the room.

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8 0
3 years ago
Hüseyin draws a fox with a scale of 3 units on his graph paper represents 15cm. The fox has an actual height of 80cm. What is th
Over [174]

Answer:

The height of the fox in Huseyin's drawing is, 16 units

Step-by-step explanation:

Proportion states that the two ratios or fractions are equal.

As per the statement: Huseyin draws a fox with a scale of 3 units on his graph paper represents 15 cm. The fox has an actual height of 80 cm.

⇒ We are given Scale of 3 units.

On graph paper the length of fox is 15 cm.

The fox has an actual height = 80 cm

let x be the height in units of the fox in Huseyin's drawing.

By definition of proportion;

\frac{3}{15} = \frac{x}{80}

by cross multiply we get;

3 \times 80 = 15x

Simplify:

240 = 15x

Divide both sides by 15 we get;

x = 16 units.

Therefore, the height of the fox in Huseyin's drawing is, 16 units


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3 years ago
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Alex is a writer who writes poems and short stories. For an upcoming writer's workshop Alex wants to write some new works. He ne
pashok25 [27]

Answer:

The maximum number of works that he can write while staying in his time budget is 24.

21 poems and 3 short stories

Step-by-step explanation:

In order to solve this problem we must first determine what our variables are. In this case it's the number of poems and short stories he can write.

p = # of poems

s = # of short stories

Next, we must build our objective function which will represent the total number of works he can write.

N=p+s

where N is the number of works.

Next, we must write the constrains based on the information provided by the problem.

The problem tells us that it takes him 30 hours to write a poem and 70 hours to write a short story and that he has 840 hours available to write them, so that constrain will be the following:

30p+70s \leq 840

it also tells us that he wants to write at least 4 poems and 3 short stories so there we have our other two constrains.

p \geq 4

s \geq 3

once we got our constrains we can go ahead and graph them to see how they will behave. (See attached picture)

In the graph p is the horizontal axis and s is the vertical axis.

On the graph we can see a polygon that is formed by the restriction. The vertices of the polygon will represent the optimal conditions for this linear programming problem. There are three optimal solutions there, so we need to test them to see which will return the greatest number of works he can write while keeping the given conditions.

Option 1:

4 poems and 3 short stories

N=4+3

N= 7 works

Option 2:

4  poems and 10 short stories

N=4+10

N=14 works

Option 3:

21 poems and 3 short stories

N=21+3

N=24 works

So the optimal solution will be given by option 3 with 21 poems and 3 short stories.

5 0
2 years ago
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