Answer:
- CFJA17
- THZ561
- GJA561
- GH68
- N461
- DG56
- BSJ57
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<span>Answer:
(4.184 J/g·°C) x (185 g) x (24.70 - 21.00)âC = 2863.948 J = 2.86 kJ
(2.86 kJ) / (2.00 mol) = 1.43 kJ/mol</span>
The name of the ion is Copper.
<u>Explanation</u>:
- Copper is a chemical element symbolized as Cu. It has different ions, one of which is Cu(2+) and Cu(1+).
- Copper on losing 2 electrons forms the ion Cu(2+)
- Copper(2+) is an ion that carries double positive charge.
- It plays the role of a cofactor.
- It is also more stable than the single positive ion Cu(1+)
Answer:
Fe²⁺ = 80mol/Ls
H⁺ = 50mol/Ls
Mn²⁺ = 4.0x10²mol/Ls
Fe³⁺ = 80mol/Ls
H₂O = 1.0x10²mol/Ls
Explanation:
Based on the reaction:
MnO₄⁻ + 5 Fe²⁺ + 8H⁺ → Mn²⁺ + 5 Fe³⁺ + 4H₂O
<em>Where 1 mole of permangante with 5 moles of Fe²⁺ and 8 moles of H⁺ produce 1 mole Mn²⁺, 5 of Fe³⁺ and 4 of H₂O</em>
<em />
If the diappearence of 1 mole has a rate of 4.0x10²mol/Ls, disappearence of 5 moles of Fe²⁺ and 8 moles of H⁺ have a rate of:
Fe²⁺ = 1 mole MnO₄⁻ × ( 4.0x10²mol/Ls / 5 moles of Fe²⁺) = 80mol/Ls
H⁺ = 1 mole MnO₄⁻ × ( 4.0x10²mol/Ls / 8 moles of H⁺) = 50mol/Ls
And rate of appearance of 1 mole Mn²⁺, 5 of Fe³⁺ and 4 of H₂O are:
Mn²⁺ = 1 mole MnO₄⁻ × ( 4.0x10²mol/Ls / 1 moles of Mn²⁺) = 4.0x10²mol/Ls
Fe³⁺ = 1 mole MnO₄⁻ × ( 4.0x10²mol/Ls / 5 moles of Fe³⁺) = 80mol/Ls
H₂O = 1 mole MnO₄⁻ × ( 4.0x10²mol/Ls / 4 moles of H₂O) = 1.0x10²mol/Ls
