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timama [110]
3 years ago
11

How can a solid dissolved in water be separated from the water?.

Chemistry
1 answer:
Alex73 [517]3 years ago
3 0

Answer:

Evaporation

Explanation:

Boiling the water will make it evaporate, leaving the solid at the bottom of the solution

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How will the vapor pressure of an aqueous solution of sodium chloride compare to that of pure water?
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3.15 mol of an unknown solid is placed into enough water to make 150.0 mL of solution. The solution's temperature increases by 1
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<u>Answer:</u> The enthalpy change of the unknown solid is 3.824 kJ/mol

<u>Explanation:</u>

To calculate the mass of solution , we use the equation:

\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}

Density of solution = 1.20 g/mL

Volume of solution = 150.0 mL

Putting values in above equation, we get:

1.20g/mL=\frac{\text{Mass of solution}}{150.0mL}\\\\\text{Mass of solution}=(1.20g/mL\times 150.0mL)=180g

The equation used to calculate heat released or absorbed follows:

Q=m\times c\times \Delta T

q = heat absorbed or released

m = mass of solution = 180 g

c =  specific heat capacity = 4.18 J/g°C

\Delta T = change in temperature = 16.01°C

Putting values in above equation:

Q=180\times 4.18\times 16.01=12045.9J=12.046kJ

To calculate the enthalpy change of the reaction, we use the equation

\Delta H_{rxn}=\frac{q}{n}

where,

q = amount of heat absorbed = 12.046 kJ

n = number of moles of solid = 3.15 moles

\Delta H_{rxn} = enthalpy change of the reaction

Putting values in above equation, we get:

\Delta H_{rxn}=\frac{12.046kJ}{3.15mol}=3.824kJ/mol

Hence, the enthalpy change of the unknown solid is 3.824 kJ/mol

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