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Vika [28.1K]
3 years ago
11

Given the following, determine ΔG°f at 298 K for SnO. Sn(s) + SnO2(s) → 2SnO(s) ; ΔG° = 12.0 kJ at 298K

Chemistry
1 answer:
Virty [35]3 years ago
3 0

Answer:

The value of change in Gibbs free energy for tin(II) oxide solid is -251.9 kJ/mol.

Explanation:

Sn(s) + SnO_2(s)\rightarrow 2SnO(s), \Delta G_{f}^{o} = 12.0 kJ

\Delta G_{f,SnO_2}^{o}= -515.8kJ/mol

\Delta G_{f,Sn}^{o}= 0 kJ/mol

\Delta G_{f,SnO}^{o}=?

\Delta G_{f}^{o}=\sum ((\Delta G_{f}^{o})_ {products})-\sum ((\Delta G_{f}^{o})_ {reactants})

12.0 kJ=(2 mol\times \Delta G_{f,SnO}^{o})-(1mol\times 0 kJ/mol+1 mol\times -515.8 kJ/mol)

\Delta G_{f,SnO}^{o}=-251.9 kJ/mol

The value of change in Gibbs free energy for tin(II) oxide solid is -251.9 kJ/mol.

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