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miss Akunina [59]
2 years ago
12

An increase in blood CO2 or a decrease in blood ph will lead to which change in respiration?

Chemistry
1 answer:
Galina-37 [17]2 years ago
5 0
Respiratory acidosis
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imagine that you're able to fully dissolve a powered substance and water what can be said about this creation
Softa [21]
We can say that the water is the solvent, and the powder is the solute. This is also a solution altogether. 

Explanation:- A solute is the thing being dissolved into the solvent. While the solvent is what when the solute is being dissolved in. Together, they make a solution. 
8 0
3 years ago
If a student's unknown is a colorless liquid and its boiling point was measured to be about 78°C
maks197457 [2]
It might be ethanol. :)
3 0
3 years ago
An atom X has 2 electrons in its outer orbit. What will it do to form a stable ion?
matrenka [14]

Answer:

In a neutral molecule, the sum of the bonding valance electrons must be equal. So the products of the negative element and its charges and the positive element and its charge must be equal.

Explanation:

C1×N1 = C2×N2

If we have a 3 valance electrons , the 'A' charge will be either +3 or -5 for a full octet and valance electron in 'B' atoms will mostly result in acquisition of additional electrons (2) for an octet and relative charge of -2.

Balancing the two,

3 × A = -2 × B

To be equal, A = 2 and B = 3

Therefore, A²B³

6 0
3 years ago
What is the molar mass of Sn(CO3)2?
Free_Kalibri [48]

Answer:

The molar mass and molecular weight of Sn(CO3)2 is 238.728.

Explanation:

7 0
3 years ago
The concentrations of the products at equilibrium are [pcl3] = 0.180 m and [cl2] = 0.250 m. what is the concentration of the rea
sineoko [7]
We have Kc = 4.2 x 10^-2 (given but missing in the question)
and When the balanced equation for this reaction is:
PCl5(g) ↔ PCl3(g) + Cl2(g)
so, according to the Kc formula:
Kc = the concentration of products / the concentration of the reactants
so, to get the concentration of the reactants in equilibrium, the concentration of the products / the concentration of the reactants should equal the Kc value which is given in the question (missing in your question).
So by substitution in Kc formula: 
Kc   = [PCl3]*[Cl2] / [PCl5]
4.2 x 10^-2 =  0.18 * 0.25 /[PCl5]
∴[PCl5] = 0.18*0.25 / 4.2x10^-2 = 1.07
So the concentration of the reactants in equilibrim = 1.07

4 0
3 years ago
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