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kumpel [21]
3 years ago
7

I need help with #2 please

Mathematics
2 answers:
Serjik [45]3 years ago
5 0
Divide 5.34 by 6 to find the cost of 1 orange. You should get .89¢
k0ka [10]3 years ago
3 0
Simply divide the cost by the number of oranges to get the price of 1 orange

5.34/6
= 0.89

So, 1 orange costs $0.89
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How many solutions are there for the system x^2+4y^2=100 and 4y-x^2=-20
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x^2 + 4y^2 = 100  ____1
4y - x^2 = -20  ____2
Add both 1 & 2 together. x^2 gets cancelled
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Then equation the becomes : y^2 + y -20 =0
Now factorise the equation: (y+5) (y-4) = 0
Solve for y :  y = -5 and y = 4
Using the values of y to find the values of x. From equation 1:
x^2 = 100 - 4y^2    x = /100 - 4y^2  (/ means square root) Replace values of y
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6 0
3 years ago
Find a round to the nearest tenth a 150 12 10cm c a=?cm
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Answer:

<h3>Using~ the ~ law~ of ~sinse:-</h3><h3>\frac{a}{SinA} =\frac{b}{SinB}</h3>
  • \frac{a}{Sin150}=\frac{b}{SinB}
  • a=\frac{10~sin~150}{Sin~12}
  • a=[24] ~cm
<h3><u>-----------------------</u></h3><h3><u>hope it helps..</u></h3><h3><u>have a great day!!</u></h3>
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Verbs is the answer my friend
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