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Afina-wow [57]
2 years ago
12

ella bought some key chains. if she paid 24$ for the key chains and each one cost the same wbole-dollar amount, how many could s

he have bought
Mathematics
2 answers:
Rainbow [258]2 years ago
7 0
You could buy 6 keychains spending 4 dollars each. 6 * 4 = $24.
Goshia [24]2 years ago
6 0
She could have bought six.

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A city has a population of 280,000 people. suppose that each year the population grows by 4.5% . what will the population be aft
Anastasy [175]

Given that population of the city is 280000.

Rate of growth of the population = r = 4.5% = 0.045

We have to find population after 15 years so time

t = 15

We can use growth formula to find the required population which is given by :

A=P(1+r)^t

Where P= starting population = 280000

r= rate of growth = 0.45

t= time = 15

now plug these values into above formula.

A=280000(1+0.45)^{15}

A=280000(1.45)^{15}

A=280000(263.34194176)

A=73735743.6928

Hence population after 15 years will be approx 73735743.

8 0
2 years ago
How can you get the variable alone in 84+c=111
VLD [36.1K]
Subtract 84 on the other side of the equal sign and bring down c and the answer you get from 111 - 84.
4 0
3 years ago
Read 2 more answers
URGENTTT! CAN SOMEONE PLEASE HELP?
miskamm [114]

Answer:

Hey there!

We have tangent 29=h/400

Thus, tangent 29 times 400=h

h=221.7 feet.

The height of the kite  is 221.7 feet.

Hope this helps :)

8 0
3 years ago
3x^2 - 4x = -2<br> Solve
amid [387]

Answer:

x =   \bigg \{\frac{ 2   - \sqrt{2} \: i }{3}, \:  \: \frac{ 2    +  \sqrt{2} \: i }{3} \bigg \}

Step-by-step explanation:

3 {x}^{2}  - 4x =  - 2 \\ 3 {x}^{2}  - 4x + 2 = 0 \\ equating \: it \: with  \\ a {x}^{2}  + bx + c = 0 \\ a = 3 \:  \: b =  - 4 \:  \: c = 2 \\  {b}^{2}  - 4ac \\  =  {( - 4)}^{2}  - 4 \times 3 \times 2 \\  = 16 - 24 \\  =  - 8  \\  \ {b}^{2}  - 4ac < 0  \\  \therefore \: given \: quadratic \: equation \: have \:  \\ imaginary \: solutios. \\  \\ x =  \frac{ - b \pm \sqrt{{b}^{2}  - 4ac } }{2a}  \\ =  \frac{ - ( - 4) \pm \sqrt{ - 8} }{2 \times 3} \\ =  \frac{ 4 \pm 2\sqrt{2} \: i }{2 \times 3}  \\  =  \frac{ 2 \pm \sqrt{2} \: i }{3} \\  \therefore \: x  = \frac{ 2   - \sqrt{2} \: i }{3}  \: or \: x  = \frac{ 2   +  \sqrt{2} \: i }{3} \:  \\  \\ x =   \bigg \{\frac{ 2   - \sqrt{2} \: i }{3}, \:  \: \frac{ 2    +  \sqrt{2} \: i }{3} \bigg \}

7 0
3 years ago
I need help fast please
Dmitrij [34]

1060 / 48 = 22.08333

0.0833 = 83/100


22 83/100

7 0
3 years ago
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