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2 years ago

What would the equation be of the relationship??

Mathematics

1 answer:

Brums [2.3K]2 years ago

6 0

I don’t really know that

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What is the LCM of 70 and 36?

Alik [6]

LCM = 1260

The lowest common factor is 1260

Hope this helps! :)

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2 years ago

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One fabric cost $15.00 for 2 yards. Another cost $37.50 for 5 yards. Do both yards cost the same? Explain.

omeli [17]

Answer:

Yes.

Step-by-step explanation:

Both yards do cost the same.

$15.00 divided by 2 is equal to 7.5.

$37.50 divided by 5 is equal to 7.5.

Therefore, both yards cost the same.

3 0

2 years ago

How do I solve this?

Len [333]

5 Girls + 3 Boys =8 (sample size)

Probability of choosing 1 boy P(1 B) = 3/8

Probability of NOT CHOOSING ANY BOY = 1-3/8 =5/8

Now apply the binomial probability to choose 3 Boys:

8C3(3/8)³(5/8)⁵ ==>P(All boys) = 0.28

7 0

2 years ago

Which of the following best defines 2/4^3

lions [1.4K]

Wheres the question?

6 0

2 years ago

The velocity of an automobile starting from rest is given by the equation below, where v is measured in feet per second and t is

maria [59]

Answer:

a. At t = 5 s

$a(5)=\frac{1785}{\left(6(5)+17\right)^2}=\frac{1785}{2209}\approx0.808 \frac{ft}{s^2}$

b. At t = 10 s

$a(10)=\frac{1785}{\left(6(10)+17\right)^2}=\frac{255}{847}\approx0.301 \frac{ft}{s^2}$

c. At t = 20 s

$a(20)=\frac{1785}{\left(6(20)+17\right)^2}=\frac{1785}{18769}\approx0.095 \frac{ft}{s^2}$

Step-by-step explanation:

We know that the velocity function is given by

$v(t)=\frac{105t}{6t+17}$

Acceleration is the rate of change of velocity so we take the derivative of the velocity function with respect to time.

$a(t)=\frac{dv}{dt}=\frac{d}{dt} (\frac{105t}{6t+17})$

$\mathrm{Take\:the\:constant\:out}:\quad \left(a\cdot f\right)'=a\cdot f\:'\\\\105\frac{d}{dt}\left(\frac{t}{6t+17}\right)\\\\\mathrm{Apply\:the\:Quotient\:Rule}:\quad \frac{d}{{dx}}\left( {\frac{{f\left( x \right)}}{{g\left( x \right)}}} \right) = \frac{{\frac{d}{{dx}}f\left( x \right)g\left( x \right) - f\left( x \right)\frac{d}{{dx}}g\left( x \right)}}{{g^2 \left( x \right)}}$

$105\cdot \frac{\frac{d}{dt}\left(t\right)\left(6t+17\right)-\frac{d}{dt}\left(6t+17\right)t}{\left(6t+17\right)^2}\\\\105\cdot \frac{1\cdot \left(6t+17\right)-6t}{\left(6t+17\right)^2}\\\\a(t)=\frac{1785}{\left(6t+17\right)^2}$

a. At t = 5 s

$a(5)=\frac{1785}{\left(6(5)+17\right)^2}=\frac{1785}{2209}\approx0.808 \frac{ft}{s^2}$

b. At t = 10 s

$a(10)=\frac{1785}{\left(6(10)+17\right)^2}=\frac{255}{847}\approx0.301 \frac{ft}{s^2}$

c. At t = 20 s

$a(20)=\frac{1785}{\left(6(20)+17\right)^2}=\frac{1785}{18769}\approx0.095 \frac{ft}{s^2}$

3 0

2 years ago