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Montano1993 [528]
3 years ago
11

Please answer these 1-4 Please answer all of them. THANSK

Mathematics
1 answer:
dalvyx [7]3 years ago
8 0
The percentage change is computed by
  percentage change = ((new value)/(original value) - 1) × 100%

Problems 1–3 all use this formula.

1. (3.25/.99 - 1)×100% ≈ 228.3%
2. (2.75/3.25 - 1)×100% ≈ -15.4%
3. (2.75/.99) - 1)×100% ≈ 177.8%

4. The formula for simple interest is
  I = Prt
where P is the principal amount, r is the rate, t is the number of periods, and I is the interest earned. Substitute the given values and solve for t.
  400 = 5000·0.04·t
  400/200 = t = 2
The money was in the bank for 2 years.
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Jenny has 50 marbles

Step-by-step explanation:

I find it easiest to right down the numbers as I read the question,

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A rectangle has height of 3,27 meters and a base measuring 1.29 meters as shown which of the following is closest to x the lengt
luda_lava [24]

Answer:

from pythogarus theorem:

x =  \sqrt{ {3.27}^{2} +  {1.29}^{2}  }  \\ x =  \sqrt{12.357}  \\ x = 3.52 \: meters

4 0
2 years ago
What are the values of the variables in the triangle below?
harkovskaia [24]

Answer:

D) x=9 ; y=3√(3)

Step-by-step explanation:

Sin(30)=\cfrac{y}{6\sqrt{3} }

\cfrac{18y}{6\sqrt{3}}=18\sin \left(30^{\circ \:}\right)

\sqrt{3}y=9

\cfrac{\sqrt{3}y}{\sqrt{3}}=\cfrac{9}{\sqrt{3}}

y=3\sqrt{3}

~

Cos(30)=\cfrac{x}{6\sqrt{3} }

\cfrac{18x}{6\sqrt{3}}=18\cos \left(30^{\circ \:}\right)

\sqrt{3}x=9\sqrt{3}

\cfrac{\sqrt{3}x}{\sqrt{3}}=\cfrac{9\sqrt{3}}{\sqrt{3}}

x=9

Therefore, x=9 and y=3√(3)

~

8 0
2 years ago
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