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jenyasd209 [6]
3 years ago
5

How many times would you expect to get heads when flipping a coin 60 times

Mathematics
2 answers:
agasfer [191]3 years ago
8 0

Answer:

30 times

Step-by-step explanation:

We have 2 outcomes, heads and tails, so to get the probability of getting heads, divide 60 by 2 to get 30. This is theoretical. Hope this helps!

Ivanshal [37]3 years ago
5 0

Answer:

32

Step-by-step explanation:

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plz HELP!! For f(x)=3x-1 find f(x) when x=2 also for g(x)=x with an exponet of 2-xfind g(x )when x= -2
mina [271]
F(2) = 3(2)-1
= 5

G(-2)=(-2)^2
= 4
4 0
3 years ago
3. The graph y = x2 - 3 is translated down 6 units. What would be the new function rule? Y=8² - 9 À​
SIZIF [17.4K]

Answer:

a= −1/9y+64/9

3 0
3 years ago
Find the increase in price of a single piece of design, when crafts design price is increased by 45% which makes a buyer to buy
Volgvan

Answer: Original price = $43.10, Increase = $19.40, Final price = $62.50

<u>Step-by-step explanation:</u>

Let x represent the original price, then

8x(1.45) < $500

x

x < $43.10

Increase is 0.45x

0.45($43.10)

= $19.40

Final price is Original + Increase

$43.10 + $19.40

= $62.50

8 0
4 years ago
Can someone please help me with this
k0ka [10]

Answer: 3x^6+x^5-x^4-6x^3+x^2+3x-1

Step-by-step explanation:

 (3x^2+x-1)(x^4-2x+1)

=3x^6-6x^3+3x^2+x^5-2x^2+x-x^4+2x-1

=3x^6+x^5-x^4-6x^3+x^2+3x-1

Hope this helps!! :)

Please let me know if you have any question

5 0
3 years ago
Read 2 more answers
Fins the value of (15)^3 + (-9)^3 + (-6)^3 , without actually cubing the numbers​
Hatshy [7]

a³ + b³ + c³ + 3abc = ( a + b + c)(a² + b² + c² + ab + bc + ca)

if a + b + c = 0. then a³ + b³ + c³ = 3abc

here a + b + c = 15 + (-9) + (-6)

a + b + c = 15 - 15

a + b + c = 0

so a³ + b³ + c³ = 3abc

15³ + (-9)³ + (-6)³ = 3(15)(-9)(-6)

= 2430

so the answer is 2430

8 0
3 years ago
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