What is the interquartile range of this data set?<br>
2,5,9,11,18, 30, 42, 48, 55, 73, 81
Lubov Fominskaja [6]
Answer:
46
Step-by-step explanation:
55-9=46
2=min
9=Lq
30=median
55= Uq
81= max
Answer:
Assuming 1/20 is a 5% late fee:
$21.211
Step-by-step explanation:
67.82 x 1/20 = 3.391
67.82 + 3.391 = 71.211
Answer:
104.8 in^2
Step-by-step explanation:
There are 2 ways to solve this problem.
The 1st way:
Let's make 2 triangles and 1 rectangle:
Rectangle Length = 8.3
Rectangle Width = 8
So, the left out length will be 17.9 - 8.3
=> 9.6
Since, 9.6 cm is for 2 parts.
=> 9.6 / 2
=> 4.8
So, Height of the Triangle = 8
Base of the triangle = 4.8
Area of a rectangle
=> 8.3 x 8
=> 66.4
Area of the triangle
=> 1/2 x 8 x 4.8
=> 4 x 4.8
=> 19.2
There are 2 triangles:
=> 19.2 x 2
=> 38.4
=> 66.4 + 38.4
=> 104.8
The area of the trapezoid = 104.8 in^2.
The 2nd way is:
Area of a trapezoid
=> Smaller Base + Larger Base / 2 x Height
=> 8.3 + 17.9 / 2 x 8
=> 26.2 / 2 x 8
=> 13.1 x 8
=> 104.8
The area of the trapezoid is 104.8 in^2
Step-by-step explanation:
123456 less then 7
unlimited greater then 7
The answer is 37/100 as a fraction. Hope this helps you.
