What is the width of a rectangle with an area fo 5\8in2 and a length of 10 inches?
1 answer:
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Answer:
Step-by-step explanation:
(3a + 2b − c) (a − b + 2c)
Expand (3a + 2b − c) (a − b + 2c) by multiplying each term in the first expression by each term in the second expression.
3a ⋅ a + 3a (−b) + 3a (2c) + 2ba + 2b (−b) + 2b (2c) − ca − c (−b) − c (2c)
3 (a ⋅ a) + 3a (−b) + 3a (2c) + 2ba + 2b (−b) + 2b (2c) − ca − c (−b) − c (2c)
3a^2 + 3a (−b) + 3a (2c) + 2ba + 2b (−b) + 2b (2c) − ca − c (−b) − c (2c)
Rewrite using the commutative property of multiplication.
3a^2 + 3 ⋅ −1ab + 3a (2c) + 2ba + 2b (−b) + 2b (2c) − ca − c (−b) − c (2c)
3a^2 − 3ab + 3a (2c) + 2ba + 2b (−b) + 2b (2c) − ca − c (−b) − c (2c)
Rewrite using the commutative property of multiplication.
3a^2 − 3ab + 3 ⋅ 2ac + 2ba + 2b (−b) + 2b (2c) − ca − c (−b) − c (2c)
3a^2 − 3ab + 6ac + 2ba + 2b (−b) + 2b (2c) − ca − c (−b) − c (2c)
Rewrite using the commutative property of multiplication.
3a^2 − 3ab + 6ac + 2ba + 2 ⋅ −1b ⋅ b + 2b (2c) − ca − c (−b) − c (2c)
3a^2 − 3ab + 6ac + 2ba + 2 ⋅ −1 (b ⋅ b) + 2b (2c) − ca − c (−b) − c (2c)
3a^2 − 3ab + 6ac + 2ba + 2 ⋅ −1b^2 + 2b (2c) − ca − c (−b) − c (2c)
3a^2 − 3ab + 6ac + 2ba − 2b^2 + 2b (2c) − ca − c (−b) − c (2c)
Rewrite using the commutative property of multiplication.
3a^2 − 3ab + 6ac + 2ba − 2b^2 + 2 ⋅ 2bc − ca − c (−b) − c (2c)
3a^2 − 3ab + 6ac + 2ba − 2b^2 + 4bc − ca − c (−b) − c (2c)
Rewrite using the commutative property of multiplication.
3a^2 − 3ab + 6ac + 2ba − 2b^2 + 4bc − ca − 1 ⋅ −1cb − c (2c)
3a^2 − 3ab + 6ac + 2ba − 2b^2 + 4bc − ca + 1cb − c (2c)
3a^2 − 3ab + 6ac + 2ba − 2b^2 + 4bc − ca + cb − c (2c)
Rewrite using the commutative property of multiplication.
3a^2 − 3ab + 6ac + 2ba − 2b^2 + 4bc − ca + cb − 1 ⋅ 2c ⋅ c
3a^2 − 3ab + 6ac + 2ba − 2b^2 + 4bc − ca + cb − 1 ⋅ 2 (c ⋅ c)
3a^2 − 3ab + 6ac + 2ba − 2b^2 + 4bc − ca + cb − 1 ⋅ 2c^2
3a^2 − 3ab + 6ac + 2ba − 2b^2 + 4bc − ca + cb − 2c^2
3a^2 − 3ab + 2ab + 6ac − 2b^2 + 4bc − ca + cb − 2c^2
3a^2 − ab + 6ac − 2b^2 + 4bc − ca + cb − 2c^2
3a^2 − ab − 2b^2 + 4bc + 6ac − 1ac + cb − 2c^2
3a^2 − ab − 2b^2 + 4bc + 5ac + cb − 2c^2
3a^2 − ab − 2b^2 + 4bc + bc + 5ac − 2c^2
3a^2 − ab − 2b^2 + 5bc + 5ac − 2c^2
3a^2 − ab − 2b^2 + 5ac + 5bc − 2c^2
3a^2 − ab + 5ac − 2b^2 + 5bc − 2c^2
Answer:
y=x+1
Step-by-step explanation:
First, let's do the easiest part, finding the y-intercept, which shows up at the end of your slope intercept equation, y=mx+b, where slope is rise over run!
- Simply look for where the coordinate is on the y-intercept, which is at y = 1!
Then, we need to find our rise over run, which is basically counting from point a to point b. To get to the lower coordinate from the top, we go down two (-2), and over 4. Which means we "rose" -2, and "ran" 4! It's -2 because we went DOWN, and positive 4 because we went FORWARD. This gave us 2 over 4, which is the same as 1 over 2!
:D