Answer:
sin(4π/21)
Step-by-step explanation:
Step 1: Rearrange expression
sin(π/3)cos(π/7) - cos(π/3)sin(π/7)
Step 2: Use sin(A ± B)
sin(π/3 - π/7)
Step 3: Evaluate
sin(4π/21)
And we have our answer!
Answer:
1) A line can be defined by two points that are connected by the given line.
We can see that the line r connects the points A and B, then we can call this line as:
AB (the notation usually uses a double arrow in top of the letters)
2) In the image we can see that lines r and s intersect at the point B, then another name for that intersection is: B.
3) 3 colinear points are 3 points that are connected by a single line, an example of this can be the points A, B and C.
4) A plane can be defined by a line and a point outside the line.
For example, we can choose the line AB and the point D, that does not belong to the line.
Then we can call the plane as ABD.
Answer:
whole milk 4 ---------------- 32 ounces
skim milk 0 ---------------- x ounces
Mixture 2.5 ---------------- 32 + x ounces
4*32+0x =2.5(32 +x)
128+0x= 80+2.5 x
0 x + -2.5 x = 80 - -128
-2.5 x = -48
/ -2.5
x = 19.2
19.2 ounces of 0 % fat skim milk
Answer:
(2x + 5) (x + 2)
Step-by-step explanation:
(2x + 5) (x + 2)
2x² + 4x + 5x + 10
2x² + 9x + 10
The normal vector to the plane <em>x</em> + 3<em>y</em> + <em>z</em> = 5 is <em>n</em> = (1, 3, 1). The line we want is parallel to this normal vector.
Scale this normal vector by any real number <em>t</em> to get the equation of the line through the point (1, 3, 1) and the origin, then translate it by the vector (1, 0, 6) to get the equation of the line we want:
(1, 0, 6) + (1, 3, 1)<em>t</em> = (1 + <em>t</em>, 3<em>t</em>, 6 + <em>t</em>)
This is the vector equation; getting the parametric form is just a matter of delineating
<em>x</em>(<em>t</em>) = 1 + <em>t</em>
<em>y</em>(<em>t</em>) = 3<em>t</em>
<em>z</em>(<em>t</em>) = 6 + <em>t</em>