Answer:
volume of the airspace=0.605m^3
Explanation:
Patm = 10^5 N/m^2
Depth= 60 metres
Pressure at the depth = ?
Density = 1.025 g/cm3 = 1025 kg/m3
P = Patm + hσg
P = 10^5 + 60*1025*9.8
P = 702700 N/m^2
P = 7.027 atm
Since the temperature is constant, Boyle’s law holds
P1V1 = P2V2
P1 = 1 atm
P1, initial pressure of the bell(atm pressure) = 1 atm
The initial volume of the airspace, V1 = 4.25 m^3
Final pressure at the depth = 7.027 atm
Applying the Boyle’s lay
1*4.25 = 7.027 * V2
V2 = 4.25/7.027
V2 = 0.605m^3
Answer:
q = 3.356×10^-6C
Explanation:
In a cube of air,the electric field is perpendicular to the top and bottom of the cube,the total reflux = reflux200 + reflux300
But reflux is given by:
Reflux= E×A = E×A cos theta.
Where theta is the angle between the area vector and the electric field.
Total reflux = E300×A cos180 + E200×A cos0
Total reflux = -E300A + E200A
Total reflux =A (E300-E200)
Total reflux is given by Guass's law = Total reflux =q/Eo
q=Eo×total reflux
q= EoA(E200-E300)q= (8.84×10^-12)(100)^2×(100-60)
q=3.356×10^-6C
The correct answer is heterozygous.
