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Leto [7]
3 years ago
11

Given equation is F=mv ×v/R what is the relationship exist between F and R?

Physics
1 answer:
irina [24]3 years ago
8 0
This is called an "inverse" relationship because the bigger R becomes, the smaller F becomes as a result. you can do a couple of calculations on your calculator to see this (just increase R and watch what happens to F).

Also, when an equation has F = (x.y)/R^2  we call this the "inverse square" relationship, since it is also inverse, but squared. In practice it means that every time you double R, F decrease by 4 times! You will see this in physics a lot, so it's good to know!
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In which scenario will the two objects have the greatest gravitational force
Brilliant_brown [7]

Answer: I think the answer C

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2 years ago
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a 20 ft shipping container on a cargo ship has a mass of 24000 kg and a volume of 33.2m3. what is the density of the shipping co
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Answer:

722.89

Explanation:

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3 0
3 years ago
What is the acceleration of a proton moving with a speed of 6.5 m/s at right angles to a magnetic field of 1.5 T?
Brilliant_brown [7]

Answer:

The acceleration of the proton is 9.353 x 10⁸ m/s²

Explanation:

Given;

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magnetic field strength, B = 1.5 T

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F = ma = qvB(sin90°)

ma = qvB

where;

m is mass of the proton, = 1.67 x 10⁻²⁷ kg

charge of the proton, q = 1.602 x 10⁻¹⁹ C

The acceleration of the proton is given by;

a = \frac{qvB}{m}\\\\a = \frac{(1.602*10^{-19})(6.5)(1.5)}{1.67*10^{-27}}\\\\a = 9.353*10^8 \ m/s^2

Therefore, the acceleration of the proton is 9.353 x 10⁸ m/s²

4 0
3 years ago
The horizontal surface on which the block (mass 2.0 kg) slides is frictionless. The speed of the block before it touches the spr
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Conserving Energy

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\frac{m(v_1^2-v_2^2)}{2}=\frac{kx^2}{2}

2\left [ 6^2-v_2^2\right ]=2\times 10^3\times \left [ 0.15\right ]^2

v_2=3.67 m/s

7 0
3 years ago
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