Answer:
true
Explanation:
Friction occurs because no surface is perfectly smooth. Rougher surfaces have more friction between them. Heavier objects also have more friction because they press together with greater force. Friction produces heat because it causes the molecules on rubbing surfaces to move faster and have more energy.
Answer:
The balloon would still move like a rocket
Explanation:
The principle of work of this system is the Newton's third law of motion, which states that:
"When an object A exerts a force on an object B (action), object B exerts an equal and opposite force (reaction) on object A"
In this problem, we can identify the balloon as object A and the air inside the balloon as object B. As the air goes out from the balloon, the balloon exerts a force (backward) on the air, and as a result of Newton's 3rd law, the air exerts an equal and opposite force (forward) on the balloon, making it moving forward.
This mechanism is not affected by the presence or absence of surrounding air: in fact, this mechanism also works in free space, where there is no air (and in fact, rockets also moves in space using this system, despite the absence of air).
Answer:
La energía interna es el resultado de la contribución de la energía cinética de las moléculas o átomos que lo constituyen, de sus energías de rotación, traslación y vibración, además de la energía potencial intermolecular debida a las fuerzas de tipo gravitatorio, electromagnético y nuclear.
Explanation:
To solve this problem we will apply the kinematic equations of linear motion and centripetal motion. For this purpose we will be guided by the definitions of centripetal acceleration to relate it to the tangential velocity. With these equations we will also relate the linear velocity for which we will find the points determined by the statement. Our values are given as


PART A )


Calculate the velocity of the motorcycle when the net acceleration of the motorcycle is 




Now calculate the angular velocity of the motorcycle



Calculate the angular acceleration of the motorcycle



Calculate the time needed by the motorcycle to reach an acceleration of




PART B) Calculate the velocity of the motorcycle when the net acceleration of the motorcycle is 




PART C)
Calculate the radial acceleration of the motorcycle when the velocity of the motorcycle is 



Calculate the net acceleration of the motorcycle when the velocity of the motorcycle is 



PART D) Calculate the maximum constant speed of the motorcycle when the maximum acceleration of the motorcycle is 



