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Dominik [7]
3 years ago
7

How are the spiral arms of the milky way detected?

Physics
1 answer:
Step2247 [10]3 years ago
6 0
The spiral structure emerges when galactic clusters (open), H II regions and O & B type stars (young stars) are used as tracers. We know this to be true as other pinwheel galaxies exhibit the same patterns across these tracers as in the milky way.
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What is cartilage?
Sphinxa [80]

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An example would be between the vertabrae in the spine.

Like the other (inappropriate) answer said, a ligament is what attches muscles and bones.

Also, the tissue inside of bones is bone marrow.

If you know that, you can take out those two options (Option 1 and 3)

5 0
2 years ago
Which of the following depends on an object's displacement not distance from the starting point?
spayn [35]
The answer is A) velocity, because velocity is speed and displacement.
Hope this helps
6 0
3 years ago
Solve this question
Rudik [331]
Ok


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6 0
3 years ago
How much voltage is required to run 0.025 A of current through a 36 Ω resistor?
aalyn [17]

Yes D is definitely the answer

<em>V</em><em>=</em><em>I×</em><em>R</em>

<em>V</em><em>=</em><em>0</em><em>.</em><em>0</em><em>2</em><em>5</em><em>×</em><em>3</em><em>6</em>

<em>V</em><em>=</em><em>0</em><em>.</em><em>9</em><em> </em><em>sa</em><em>me</em><em> </em><em>as</em><em> </em><em>0</em><em>.</em><em>9</em><em>0</em>

7 0
3 years ago
A sled is pulled with a horizontal force of 18 n along a level trail, and the acceleration is found to be 0.39 m/s2. an extra ma
Natali5045456 [20]
From Newton's second law of motion, it is identified that the net force applied to the object with mass m, will make it move with an acceleration of a. This can be mathematically translated as,
                        F = m x a
To solve for the mass of the sled, we derive the equation above such that,
                        m = F / a
Substituting,
                       m = (18 N) / (0.39 m/s²)
                          m = 46.15 kg

Then, we add to the calculated mass the mass of the extra material.
                      total mass = 46.15kg + 4.5 kg
                       total mass = 50.65 kg
We solve for the normal force of the surface to the object by calculating its weight.
                     F₂ = (50.65 kg)(9.8 m/s²)
                     F₂ = 496.41 N

The force that would allow barely a movement for the object is equal to the product of the normal force and the coefficient of kinetic friction.
                     F = (F₂)(c)
                      c = F/F₂

Substituting,
                      c = 18 N/496.41 N
                       c = 0.0362

<em>ANSWER: c = 0.0362</em>

5 0
3 years ago
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