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3 years ago

How are the spiral arms of the milky way detected?

1 answer:

6 0

The spiral structure emerges when galactic clusters (open), H II regions and O & B type stars (young stars) are used as tracers. We know this to be true as other pinwheel galaxies exhibit the same patterns across these tracers as in the milky way.

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what is the answer to the question "Two boys of equal mass go up to the first floor of a building. Boy A takes the stairs, boy B

weeeeeb [17]

Answer:

Explanation:e

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3 years ago

A cannon sends a projectile towards a target a distance 1420 m away. The initial velocity makes an angle 35◦ with the horizontal

ss7ja [257]

Answer:

$v_{o}=141.51m/s$

Explanation:

From the exercise we know the final x distance, the angle which the projectile is being released and acceleration of gravity

$x=1420m\\g=-9.8m/s^{2}$

From the equation of x-position we know that

$x=v_{ox}t=v_{o}cos(35)t$

Solving for $v_{o}$

$v_{o}=\frac{x}{tcos(35)} =\frac{1420m}{tcos(35)}$ (1)

Now, if we analyze the equation of y-position we got

$y=y_{o}+v_{oy}t+\frac{1}{2}gt^{2}$

At the end of the motion y=0

$0=v_{o}sin(35)t+\frac{1}{2}gt^{2}$

Knowing the equation for $v_{o}$ in (1)

$0=\frac{1420}{tcos(35)}tsin(35)-\frac{1}{2}(9.8)t^{2}$

$\frac{1}{2}(9.8)t^{2}=1420tan(35)$

Solving for t

$t=\sqrt{\frac{2(1420tan(35))}{9.8} } =14.25s$

Now, we can solve (1)

$v_{o}=\frac{1420m}{(14.25s)cos(35)}=141.51m/s$

6 0

3 years ago

Read 2 more answers

1. On one of the shelves in your physics lab is displayed an antique telescope. A sign underneath the instrument says that the t

Ira Lisetskai [31]

Answer:

a) $f_{e}$ = 3,375 cm , b) f₀ = 77.625 cm

Explanation:

The magnification of a telescope is, to see at the far point of vision (infinity image)

m = - f₀ / $f_{e}$

The length of the tube is

L = f₀ + $f_{e}$

a) The focal length of the eyepiece

L = - m $f_{e}$ + $f_{e}$

L = $f_{e}$ (1-m)

$f_{e}$ = L / (1-m)

Let's calculate

$f_{e}$ = 81.0 / (1 - (-23.0)

$f_{e}$ = 3,375 cm

b) the focal length of the target

f₀ = -m $f_{e}$

f₀ = 23 (3.68)

f₀ = 77.625 cm

8 0

3 years ago

A man applies a force of 100 Newtons to a rock for 60 seconds, but the rock does not not move. What is the amount of work done b

frozen [14]

Well if the rock doesn't move, then there is no amount of work done. There is no work done on an object if a force is applied to the object but it DOES NOT change its position, in this case is the rock.

7 0

3 years ago

If Paula travels 3 km south and turns and goes 4 km east, what is the total displacement? What is the total distance? Please Exp

Ulleksa [173]

N
W E
S
Paula has gone 1 km east as the total displacement. The total distance would be 7 km. Why? Well, the difference between displacement and distance is displacement is directional which is why it’s included in velocity and not speed. However, distance is more broad and not as specific.

3 0

2 years ago