Answer:
The statement, which correctly describes the motion of the buses is this: THE AVERAGE SPEED OF THE BUSES IS EQUAL.
Speed is defined as the distance traveled per unit time; it measures the rate of moving of an object. It is a scalar quantity, that is, it has only magnitude and no specific direction and it is measured in meter per second. A high speed value implies that an object is moving very fast while a low value indicates that the object is moving slowly. For the two buses given in the question, they both moved the same distance in the same amount of time.
Answer:
im no proffesional
Explanation:
but i tghink you need a proffessional for this one
The velocity of the red cart after the collision is 2 m/s
From the law of conservation of momentum, initial momentum of system = final momentum of system.
m₁v₁ + m₂v₂ = m₁v₃ + m₂v₄ where m₁ = mass of red cart = 4 kg, v₁ = velocity of red cart before collision = + 4 m/s, v₃ = velocity of red cart after collision, m₂ = mass of blue cart = 1 kg, v₂ = velocity of blue cart before collision = 0 m/s (since it is initially at rest) and v₄ = velocity of blue cart after collision = + 8 m/s.
Substituting the values of the variables into the equation, we have,
m₁v₁ + m₂v₂ = m₁v₃ + m₂v₄
4 kg × 4 m/s + 1 kg × 0 m/s = 4v₃ + 1 kg × 8 m/s
16 kgm/s + 0 kgm/s = 4v₃ + 8 kgm/s
16 kgm/s = 4v₃ + 8 kgm/s
16 kgm/s - 8 kgm/s = (4 kg)v₃
(4 kg)v₃ = 8 kgm/s
Divide both sides by 4 kg, we have
v₃ = 8 kgm/s ÷ 4 kg
v₃ = 2 m/s
The velocity of the red cart after the collision is 2 m/s.
Learn more about conservation of momentum here:
brainly.com/question/7538238
Answer:
Explanation:
The equation for this is the one for the Law of Momentum Conservation which says that the momentum before the collision of the balls has to be the same after the collision because momentum cannot be created or destroyed. For us in particular:
and filling in:
[(4.0)(6.0) + (2.0)(0)] = [(4.0 + 2.0)v] and
24 + 0 = 6.0v and
24 = 6.0v so
v = 4.0 m/s to the right