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3 years ago

Charges flow from_ voltage to__ voltage.

Physics

1 answer:

iogann1982 [59]3 years ago

5 0

Answer:

high to low

Explanation:

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23) What is the magnitude of the electric field intensity at a point where a proton experiences an

Radda [10]

Answer: I am so sorry i hadn't learned this Yet~!

Explanation:

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2 years ago

An object experiences an acceleration of -6.8m/s^2. As a result, it accelerates from 54m/s to a complete stop. how much distance

Kipish [7]

Answer:

210 m

Explanation:

Given:

a = -6.8 m/s²

v₀ = 54 m/s

v = 0 m/s

Find: Δx

v² = v₀² + 2aΔx

(0 m/s)² = (54 m/s)² + 2 (-6.8 m/s²) Δx

Δx ≈ 210 m

6 0

3 years ago

You are holding a block of wood with dimensions 3 cm x 6 cm x 9 cm on the

Ainat [17]

Answer:

The normal force of weight will not differ for different placements but the force of pressure applied to the surface of your hand is per unit area. So the side with the smallest area.. 3 cm x 6 cm will exert the most pressure on your hand.

Please Give Brainliest

3 0

4 years ago

You're driving your new sports car at 85 mph over the top of a hill that has a radius of curvature of 525 m.

Bumek [7]

Explanation:

It is given that,

Speed of the sports car, v = 85 mph = 37.99 m/s

The radius of curvature, r = 525 m

Let $W_N$ is the normal weight and $W_A$ is the apparent weight of the person. Its apparent weight is given by :

$W_A=mg-\dfrac{mv^2}{r}$

So, $\dfrac{W_A}{W_N}=\dfrac{mg-\dfrac{mv^2}{r}}{mg}$

$\dfrac{W_A}{W_N}=\dfrac{g-\dfrac{v^2}{r}}{g}$

$\dfrac{W_A}{W_N}=\dfrac{9.8-\dfrac{(37.99)^2}{525}}{9.8}$

$\dfrac{W_A}{W_N}=0.719$

$\dfrac{W_A}{W_N}=71.9\%$

Hence, this is the required solution.

5 0

4 years ago

1. Swordfish are capable of stunning output power for short bursts. A 650 kg swordfish has a cross-sectional area of 0.92 m2 and

Oksana_A [137]

Answer:

$P_{sp}=178.4W/kg$

Explanation:

From the question we are told that:

Mass of fish $m_f=650kg$

Cross-sectional area $A=0.92 m^2$

Drag coefficient of $\mu= 0.0091$

Seawater density $\rho= 1026 kg/m^3.$

Speed of Fish $v=30 m/s$

Generally the equation for Drag force F_d is mathematically given by

$F_d = \mu * \rho *A v^2 /2$

$F_d = 0.0091* 0.92* 1026* 30^2/2 \\F_d= 3865. 35 N$

Generally the equation for high speed Power $P_{sp}$ is mathematically given by

$P_{sp}=3865*35*\frac{v}{m_f}$

$P_{sp}=F_d*35*\frac{30}{650}$

$P_{sp}=178.4W/kg$

5 0

3 years ago

Charges flow from___ voltage to____ voltage.

Charges flow from_ voltage to__ voltage.