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3 years ago

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Metals are good conductors of electricity because __________ . A) they are easily reduced and oxidised. B) they are easily ionis

ed C) their valence electrons are not localised D) they are ductile. E) they can be drawn into wires.

1 answer:

Advocard [28]3 years ago

3 0

Answer:

a

Explanation:

because they are easily reduced and oxidised

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What is the input of energy for a device that provides 50 units of useful energy and has an efficiency of 0.55?

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If that's the case, then

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Divide each side by 0.55 :

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Consider a large 1.54 V carbon-zinc dry cell used in a physics lab to supply 2.15 A to a circuit. The internal resistance of the

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<h2>Answer:</h2>

1.77V

<h2>Explanation:</h2>

The electromotive force voltage (E) in a cell, is related to the lost voltage ( $V_{L}$ ) and the terminal voltage ( $V_{T}$ ) as follows;

E = $V_{T}$ - $V_{L}$

Where;

The lost voltage ( $V_{L}$ ) is the product of the internal resistance (r) of the cell and current (I) in the cell. i.e

$V_{L}$ = I x r

<em>Substitute </em> $V_{L}$ <em> = I x r into equation (i) as follows;</em>

E = $V_{T}$ - (I x r) ----------------------(ii)

<em>According to the question;</em>

E = 1.54V

I = 2.15A

r = 0.105Ω

<em>Substitute these values into equation(ii) as follows;</em>

1.54 = $V_{T}$ - (2.15 x 0.105)

1.54 = $V_{T}$ - (0.22575)

1.54 = $V_{T}$ - 0.22575

<em>Solve for </em> $V_{T}$ <em>;</em>

$V_{T}$ = 1.54 + 0.22575

$V_{T}$ = 1.54 + 0.22575

$V_{T}$ = 1.77V

Therefore, the terminal voltage of the cell is 1.77V

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Answers with explanation

1)

Transmission

If all the light passes through a medium without any absorption then transmittance is 100%.

2)

Refraction

Refraction is the bending of a wave when it enters a medium where its speed is different and rays are again refracted when they leave that medium,

3)

Reflection

Reflected rays don't pass through the medium instead rays bounces off an object at an angle.

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3 years ago

A 60 cm diameter wheel accelerates from rest at a rate of 7 rad/s2. After the wheel has undergone 14 rotations, what is the radi

Mamont248 [21]

Answer:

$a=368.97\ m/s^2$

Explanation:

Given that,

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Let t is the time. Using second equation of kinematics can be calculated using time.

$\theta=\omega_it+\dfrac{1}{2}\alpha t^2\\\\t=\sqrt{\dfrac{2\theta}{\alpha }} \\\\t=\sqrt{\dfrac{2\times 87.96}{7}} \\\\t=5.01\ s$

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So, the required acceleration on the edge of the wheel is $368.97\ m/s^2$ .

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