Answer:
The speed of the spider is v = (2g*L*(1-cosθ))^1/2
Explanation:
using the energy conservation equation we have to:
Ek1 + Ep1 = Ek2 + Ep2
where
Ek1 = kinetic energy = 0
Ep1 = potential energy = m*g*L*cosθ
Ek2 = (m*v^2)/2
Ep2 = m*g*L
Replacing, we have:
0 - m*g*L*cosθ = (m*v^2)/2 - m*g*L
(m*v^2)/2 = m*g*L*(1-cosθ)
v^2 = 2g*L*(1-cosθ)
v = (2g*L*(1-cosθ))^1/2
<span>1200 meters is less than 1 kilometer
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Glucose.... have a nice day
Answer:
2 /s north
Explanation:
Given that,
Velocity due North is 8 m/s and due south is 6 m/s
We need to find the magnitude and the direction of the resulting velocity.
Let North is positive and South is negative. When two velocities are in opposite direction, they adds up. So,

It is positive. So, it is in North direction.