Answer:
so m = 3 ,4 wavelength between 410 to 660 nm so 484.25 nm and 645.6 nm light produce principal maximum
Explanation:
given data
grating =2605 lines per centimeter
angle = 30.3°
wavelengths between 410 and 660 nm
to find out
two wavelengths of the incident light that could have produced this maximum
solution
we know diffraction grating has 2605 lines / cm
so d = ( 1/ 2605 cm )
and we know equation
d sinθ = m× λ
so λ = d sinθ / m
θ = 30.3 so sin30.3 =
λ = (1/2605) sin30.3 / m
λ = (1937 nm ) / m
here put m = 1 , 2 , 3 , 4
if m = 1
λ = (1937 nm ) / 1 = 1937 nm
if m = 2
λ = (1937 nm ) / 2 = 968.5 nm
if m = 3
λ = (1937 nm ) / 3 = 645.6 nm
if m = 4
λ = (1937 nm ) / 4 = 484.25 nm
so that m = 3 ,4 wavelength between 410 to 660 nm so 484.25 nm and 645.6 nm light produce principal maximum
and longest wavelength is between 410 to 660 nm is 645.6 nm
Answer:
19.6m/s
Explanation:
Given parameters:
Initial velocity = 0m/s
Time = 2s
Unknown:
Average velocity = ?
Solution:
We can use the final velocity of the ball before landing to determines its average velocity ;
Using;
v = u + gt
v is the final velocity
u is the initial velocity
g is the acceleration due to gravity
t is the time
v = 0 + 9.8 x 2 = 19.6m/s
Answer:1 a. 2 b, 3 b. 4 a, 5 d, 6 a, 7 b, 8 a, 9 a, 10 a, 11 b, 12 b, 13 a, 14 d, 15 a.
Explanation:
Speed of ball is 19.80 m/s .
<u>Explanation:</u>
We have , a 2.0 kg ball is resting at the top of a 20 m hill. if the ball rolls down the entire hill,We need to find how fast will it be going.Let's find out:
We know that,
Potential energy : This is the energy possessed by an object due to it's virtue of height and is given by , where m is mass , g is acceleration due to gravity & h is height !
Kinetic energy : This is the energy possessed by an object due to it's virtue of motion and is given by , where m is mass & v is the velocity of object !
By conservation of energy :
⇒
⇒
⇒
According to question , h=20 m i.e.
⇒
⇒
⇒
Hence , Speed of ball is 19.80 m/s .