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Xelga [282]
3 years ago
11

Based on nuclear stability, what is the symbol for the most likely product nuclide when iodine-123 undergoes decay?

Chemistry
1 answer:
MissTica3 years ago
6 0
Answer is: Te (tellurium).
During electron capture, iodine-123 f<span>orm the nearly-stable nuclide tellurium-123.
</span>In beta plus decay (atomic number Z is decreased by one), a proton is converted to a neutron and positron and an electron neutrino, so mass <span>number does not change.
</span>Iodine-123 is a radioactive isotope of iodine used in nuclear medicine imaging.<span>
</span>
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Mole of C3H8 = 26.77 moles

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