Answer:
7.71 × 10⁻⁴ M/s
Explanation:
The initial rate of the reaction can be expressed by using the formula:
![\dfrac{\Delta [O_2]}{\Delta t}](https://tex.z-dn.net/?f=%5Cdfrac%7B%5CDelta%20%5BO_2%5D%7D%7B%5CDelta%20t%7D)
where the number of moles of O₂ = 
where;
Pressue P = 1.00 atm
Volume V =5.74mL = (5.74 /1000) L
Rate R = 0.082 L atm/mol.K
Temperature = 298 K
= 2.35 × 10⁻⁴ mol
Δ[O₂] = 
Δ[O₂] = 
Δ[O₂] = 0.04626 M
The initial rate =
= 
= 7.71 × 10⁻⁴ M/s
C. Hydropower would need dams to be built, and this will prevent fishes from going upstream.
Answer:
No energy is gained or lost when molecules collide. The molecules in a gas take up a negligible (able to be ignored) amount of space in relation to the container they occupy. The molecules are in constant, linear motion.
Explanation:
Hope this helps!
Answer:
9.18g
Explanation:
Step 1: Write the reduction half-reaction
Au³⁺(aq) + 3 e⁻ ⇒ Au(s)
Step 2: Calculate the mass of gold is produced when 15.0A of current are passed through a gold solution for 15.0min
We will use the following relationships:
- 1 mole of electrons has a charge of 96486 C (Faraday's constant).
- 1 mole of Au is produced when 3 moles of electrons circulate.
- The molar mass of Au is 196.97 g/mol.
The mass of gold produced is:
Answer:
The amount of gas is what I came up with
