Since 569324 mL = 569.324 L which is much more than 1.33 L that means it cannot be diluted to a volume of 1.33 L, so this must be 569.324 mL.
This question is solved by using the dilution equation which is :
Where = Initial concentration
= Initial volume
= Final concentration
= Final volume
In our question , the given information is : V1 = 569.324 mL
M2 = 4.87 M and V2 = 1.33 L and we need to find .
When we use dilution equation we need to make sure that both the units of volume have same units.
is in 'mL' and is in 'L' , so we will first convert into 'L'
=
= 0.569324 L
Now we will plug in the values of , in dilution equation and will calculate the value of .
(Initial concentration) = 11.38 M
Water is a liquid
carbon is a solid
nitrous is a gas
Answer:
The distance the truck traveled is 190
Explanation:
I added 30, 45, 50, 65 together to get the total distance
It has lost electrons as electrons are negatively charged particles, hence a loss of electrons will leave the rod positively charged.
Always before starting any calculation it is important to verify that the reaction is balanced. To do this we count the number of atoms of each element on both sides of the reaction. When counting them we have to:
Carbon (C) - 1 atoms
Hydrogen (H) - 4 atoms
Oxygen (O) - 1 atoms
The reaction is balanced, now we proceed to see the stoichiometry of the reaction. We see that for two moles of O2 that react, 1 mole of CO2 is formed, that is, the ratio is 2 to 1.
We must calculate the moles of O2 that correspond to 370.2 grams, for this we use the molar mass of O2 (31.998g/mol).
Now, the moles of CO2 produced theoretically will be:
The grams corresponding to the 5.8 moles of CO2 produced will be the theoretical yield of the reaction, and we find it using the molar mass of CO2 equal to 44.01g/mol:
The grams of CO2 found to correspond to the theoretical yield, now the percent yield is found with the following equation:
Actual yield=85.9g of CO2
Theoretical yield=254.6g of CO2
The percent yield of the reaction is 33.7%