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Ainat [17]
1 year ago
8

The solutions that are used in this experiment have alcohols as both the solvent and the reactant. How is the excess alcohol rem

oved?.
Chemistry
1 answer:
ElenaW [278]1 year ago
4 0

Excess alcohol is removed by Vacuum filtration.

<h3>What is vacuum filtration?</h3>
  • Vacuum filtration is a methodology where a tension differential is kept up with across the channel medium by clearing the air beneath the channel paper.
  • Vacuum filtration gives a power on the arrangement notwithstanding that of gravity and builds the pace of filtration.
  • Vacuum filtration is the standard strategy utilized for isolating a strong fluid blend when the objective is to hold the strong (for instance in crystallization).
<h3>How do you dry a product after vacuum filtration?</h3>
  • The strong can be dried rapidly by washing the strong with an unpredictable fluid (methanol, CH3)2CO, or ether are normal) that the strong won't break up in. In the event that the filtrate is to be gathered, change the getting jar prior to washing.

To learn more about vacuum filtration from the given link

brainly.com/question/24082009

#SPJ4

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By titration, it is found that 28.5 mL of 0.183 M NaOH(aq) is needed to neutralize 25.0 mL of HCl(aq). Calculate the
maksim [4K]

Answer:

0.209M

Explanation:

M1V1=M2V2

(28.5 mL)(0.183M)=(25.0mL)(M)

M2= 0.209M

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4 0
2 years ago
If you combine 27.1 g of a solute that has a molar mass of 27.1 g/mol with 100.0 g of a solvent, what is the molality of the res
baherus [9]

<u>Answer:</u> The molality of the solution is 0.1 m.

<u>Explanation:</u>

To calculate the molality of solution, we use the equation:

Molality=\frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ in grams}}

Where,

m_{solute} = Given mass of solute = 27.1 g

M_{solute} = Molar mass of solute = 27.1 g/mol

W_{solvent} = Mass of solvent = 100 g

Putting values in above equation, we get:

\text{Molality of solution}=\frac{27.1\times 1000}{27.1\times 100}\\\\\text{Molality of solution}=0.1m

Hence, the molality of the solution is 0.1 m.

8 0
3 years ago
Read 2 more answers
What is the volume of an oxygen tank if it contains 12 moles of oxygen at 273 K under 75 kPa?
Zina [86]
Given:
n = 12 moles of oxygen
T = 273 K, temperature
p = 75 kPa, pressure

Use the ideal gas law, given by
pV=nRT \\ or \\  V= \frac{nRT}{p}
where
V = volume
R = 8.3145 J/(mol-K), the gas constant

Therefore,
V= \frac{(12\,mol)(8.3145\, \frac{J}{mol-K} )(273\,K)}{75 \times 10^{3} \, Pa}= 0.3632\,m^{3}

Answer: 0.363 m³
    
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Biphenyl, c12h10, is a nonvolatile, nonionizing solute that is soluble in benzene, c6h6. at 25 °c, the vapor pressure of pure be
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To completely convert 9. 0 moles of hydrogen gas (h2) to ammonia gas, how many moles of nitrogen gas (n2) are required?
evablogger [386]

To completely convert 9. 0 moles of hydrogen gas (h2) to ammonia gas, 3.0 moles of nitrogen gas (n2) are required.

<h3>What are moles?</h3>

The mole is a SI unit of measurement that is used to calculate the quantity of any substance.

<h3 />

The given reaction is \rm  N_2(g) + 3H_2(g) \rightarrow 2NH_3(g)

By the stoichiometry rule of ratio hydrogen: nitrogen

3 : 1

The reacted moles of nitrogen is equals to H/3 moles of reacted hydrogen

So, moles of nitrogen  

\rm Moles\; of\; nitrogen = \dfrac{9.0 }{3} =3.0\;mol

Thus, 3.0 moles of nitrogen gas (n2) are required.

Learn more about moles

brainly.com/question/26416088

#SPJ4

3 0
2 years ago
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