The simplest level at which life may exist is a cell
Answer:
there are 2.2 moles of Li in 15 grams of Li
By use of ideal gas equation PV= nRT where n is the number of moles,P = pressure, V = volume, R= gas constant (0.08206 L. atm/ mol.k) ant T is the temperature,
to calculate the number of moles(n) =PV/RT
convert ml to L, that is 200/1000= 0.2 L
convert mmHg to atm, that is 780mm hg x 1atm/ 760 mm hg= 1.026 atm
convert temperature to kelvin, that is 135 +273= 408 k
n is therefore= (0.2 x 1.026)/ ( 0.08206 x 408)= 6.129 x10^-3 moles
from avogadro constant 1moles = 6.02 x10^23 molecules what about 6 .129 x10^-3 moles
= ( 6.02 x10^23) x (6.129 x10^-3)/ 1mole = 3.69 x10^21 molecules
Answer:
h. 37.5 cm³
Explanation:
- We can use the general law of ideal gas: <em>PV = nRT.
</em>
where, P is the pressure of the gas in atm.
V is the volume of the gas in L.
n is the no. of moles of the gas in mol.
R is the general gas constant,
T is the temperature of the gas in K.
- If n and P are constant, and have different values of V and T:
<em>(V₁T₂) = (V₂T₁). </em>
V₁ = 50.0 cm³, T₁ = -73°C + 273 = 200 K,
V₂ = ??? cm³, T₂ = -123°C + 273 = 150 K.
∴ V₂ = (V₁T₂)/(T₁) = (50.0 cm³)(150 K)/(200 K) = 37.5 cm³.
- <em>So, the right choice is: </em><em>h. 37.5 cm³.</em>
