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Ainat [17]
2 years ago
8

The solutions that are used in this experiment have alcohols as both the solvent and the reactant. How is the excess alcohol rem

oved?.
Chemistry
1 answer:
ElenaW [278]2 years ago
4 0

Excess alcohol is removed by Vacuum filtration.

<h3>What is vacuum filtration?</h3>
  • Vacuum filtration is a methodology where a tension differential is kept up with across the channel medium by clearing the air beneath the channel paper.
  • Vacuum filtration gives a power on the arrangement notwithstanding that of gravity and builds the pace of filtration.
  • Vacuum filtration is the standard strategy utilized for isolating a strong fluid blend when the objective is to hold the strong (for instance in crystallization).
<h3>How do you dry a product after vacuum filtration?</h3>
  • The strong can be dried rapidly by washing the strong with an unpredictable fluid (methanol, CH3)2CO, or ether are normal) that the strong won't break up in. In the event that the filtrate is to be gathered, change the getting jar prior to washing.

To learn more about vacuum filtration from the given link

brainly.com/question/24082009

#SPJ4

You might be interested in
Is running water potential or kinetic energy
Mandarinka [93]

Answer:

kinetic energy

Explanation:

First you have to know the difference between potential and kinetic energy

POTENTIAL ENGRGY: energy possessed by a body by virtue of its position relative to others, stresses within itself, electric charge, and other factors.

kinetic energy: energy which a body possesses by virtue of being in motion.

An easy way to say it is kinetic energy is the energy of motion.

I hoped that helped you!

5 0
4 years ago
How many milliliters of sodium metal, with a density of 0.97 g/mL, would be needed to produce 43.6 grams of sodium hydroxide in
GaryK [48]

Answer is: 25.84  milliliters of sodium metal.

Balanced chemical reaction: 2Na + 2H₂O → 2NaOH + H₂.

d(Na) = 0.97 g/mL; density of sodim.

m(NaOH) = 43.6 g; mass of sodium hydroxide.

n(NaOH) = m(NaOH) ÷ M(NaOH).

n(NaOH) = 43.6 g ÷ 40 g/mol.

n(NaOH) =1.09 mol; amount of sodium hydroxide.

From chemical reaction: n(NaOH) : n(Na) = 2 : 2 (1: 1).

n(Na) = 1.09 mol.

m(Na) = 1.09 mol · 23 g/mol.

m(Na) = 25.07 g; mass of sodium.

V(Na) = m(Na) ÷ d(Na).

V(Na) = 25.07 g ÷ 0.97 g/mL.

V(Na) = 25.84 mL.

7 0
4 years ago
An equilibrium mixture of CO, O2 and CO2 at a certain temperature contains 0.0010 M CO2 and 0.0100 M O2. At this temperature, Kc
Naya [18.7K]
The correct answer to this question is letter "B) 8.4 × 10-4 M."

2CO+O2<->2CO2

-x       -x        +x

It started as 2CO2 so +x, then it decomposed into 2CO and O2, so-x

2CO-oxidized, O2-Oxidized, 2CO2-reduced


the easiest way is to look at the equation, so if we have some reactant and no product 

A<->2C+D

-x    +2x +x
so if we had product concentration, and no reactant concentration 3A<-> C+D +3x -x-x <span>
</span>
8 0
4 years ago
Read 2 more answers
An 8 oz serving of whole milk has 8.0 g of fat, 8.0 g of protein, and 13 g of carbohydrates. Approximately how many kilocalories
dsp73
<h3>Answer:</h3>

156 calories

<h3>Explanation:</h3>
  • Carbohydrates, proteins and fats are food substances used by living organisms to generate energy required for the day to day activities.
  • They supply energy which differs per gram for each food substance.
  • That is;

1 g of carbohydrate = 4 calories

1 g of fat = 9 calories

1 g of protein = 4 calories

Therefore, whole milk serving containing 8.0 g of fat, 8.0 g of protein and 13 g of carbohydrates will contain the following number of calories;

8.0 g of fat = 8 g × 9 cal/g = 72 calories

8.0 g of protein = 8 g × 4 cal/g = 32 calories

13 g of carbohydrates = 13 g × 4 cal/g = 52 calories

Total amount of energy = 156 calories

Therefore, an 8 oz serving of whole milk contains 156 calories

8 0
3 years ago
How many grams of NaOH are produced with the reaction of 5.00 moles of water?
just olya [345]

Answer:

Explanation:

        6.90 mol                         x grams

2As +         6NaOH           =              2Na3AsO3     + 3H2

                 6 mol                              2 mol

                                                       192 g/mol

6.90 mol NaOH  x  2 mol Na3AsO3/6 mol NaOH== 2.3 mol Na3AsO3

2.3 mol Na3AsO3  x  192 g/mol = 442 g Na3AsO3

4 0
3 years ago
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