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Marina CMI [18]
3 years ago
10

The hydrogen ion concentration of a vinegar solution is 0.00010 m. how is this concentration written in scientific notation?

Chemistry
2 answers:
mote1985 [20]3 years ago
8 0

0.00010 written in scientific notation is 1.0 * 10^-4.

Scientific notation refer to the standard manner of writing numbers that are too small or that are too big in such a way that it will be convenient to involve them in calculations and also easier to compare them. Another name for scientific notation is standard form. The format of scientific notation is Z * 10^a, where Z can be any number between 1 and 9 and a is an integer, which can be positive or negative. For the number given in the question, the number of zeros at the back of 1 is counted [there are four zeros] and this number is written as an index of 10. A negative sign is added to the number because of the decimal point in the figure.

9966 [12]3 years ago
3 0
We are given with a vinegar with a hydrogen ion concentration of 0.00010 m. We are asked to express this concentration in scientific notation. The answer when expressed in scientific notation is 1x10^-4 m or molality. Answer is <span>1x10^-4 m. </span>
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Alenkasestr [34]
<h2>1.25 g of CO_2 would be produced from the complete reaction of 25 mL of 0.833 mol/L HC_3H_3O_2 with excess NaHCO_3 </h2>

Explanation:

To calculate the number of moles for given molarity, we use the equation:

\text{Molarity of the solution}=\frac{\text{Moles of solute}\times 1000}{\text{Volume of solution (in L)}}    

0.833M=\frac{\text{Moles of} HC_3H_3O_2\times 1000}{25ml}\\\\\text{Moles of} HC_3H_3O_2 =\frac{0.833mol/L\times 25}{1000}=0.0208mol

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According to stoichiometry:

1 mole of HC_2H_3O_2 will give = 1 mole of CO_2

0.0208 moles of HC_2H_3O_2 will give =\frac{1}{1}\times 0.0208=0.0208 moles of CO_2

Mass of HC_2H_3O_2=moles\times {\text {molar mass}}=0.0208\times 60g/mol=1.25g

Thus 1.25 g of CO_2 would be produced from the complete reaction of 25 mL of 0.833 mol/L HC_3H_3O_2 with excess NaHCO_3

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