Question

The length of a rectangle is 5cm greater than its width. The perimeter is 58. What are the dimensions of the rectangle

Answer 1

Perimeter= 2w+2l
l=w+5

Substitute for l
p= 2w+2(w+5)
p= 2w+2w+10
p= 4w+10
58=4w+10
48=4w
12= w

Plug in the width to find length.
l= 12+5
l=17

Final answer: Length-17 cm, Width-12 cm

Answer 2

Write two equations:
l + w = 58
l + 5 = w
substitute and solve
l + l + 5 = 58
2l = 53
l=26.5
w=31.5
26.5cm x 31.5cm