(ax + b)/c ≤ b
ax+b ≤ cb
ax ≤ cb - b
x ≤ (cb-b)/a
Answer:
131.41 degrees
Step-by-step explanation:
Given the equation
5(sinθ+3) = sinθ+12
5sinθ+15 = sinθ+12
5sinθ-sinθ = 12 - 15
4sinθ = -3
sinθ = -3/4
θ = arcsin(-0.75)
θ = -48.59 degrees
Since sin is negative in the 3rd quadrant
α = 180 + θ
α = 180 - 48.59
α = 131.41degrees
Hence the required angle is 131.41 degrees
I need to see more in order for me to answer this question for you...
For this case we have the following parent function:
f (x) = x ^ 2
We apply the following function transformation:
Horizontal translations
Suppose that h> 0
To graph y = f (x + h), move the graph of h units to the left.
We have then:
y = (x + 3) ^ 2
Vertical translations
Suppose that k> 0
To graph y = f (x) + k, move the graph of k units up.
We have then:
y = (x + 3) ^ 2 + 4
Answer:
The graph g (x) is the graph f (x) 3 units to the left and 4 units up:
y = (x + 3) ^ 2 + 4