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scZoUnD [109]
3 years ago
6

Suppose that in 20% of all traffic accidents involving an injury, driver distraction in some form (for example, changing a radio

station or texting) is a factor. Find the probability that in a random sample of 275 such accidents between 15% and 25% involve driver distraction in some form. Assume the sample is large enough that the normal distribution applies
Mathematics
1 answer:
Ghella [55]3 years ago
6 0

What is your question?

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What us the ratio of 8 pennies and 20 dimes
inysia [295]
The ratio would be 8:20 or 8 to 20
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3 years ago
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What is the product of a+3 and −2a2+15a+6b2?
zhannawk [14.2K]

Answer:

-2a³+9a²+45a+6ab²+18b²

Step-by-step explanation:

(a+3)(-2a²+15a+6b²)

Distribute the a:

-2a³+15a²+6ab²

Then distribute the 3:

-6a²+45a+18b²

Now add both of the results together:

-2a³+15a²+6ab²-6a²+45a+18b²

Combine like terms:

-2a³+9a²+45a+6ab²+18b²

8 0
2 years ago
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Mary said that the temperature outside on two differnt days had an absolute value 20. Kate said she was wrong because the temper
TiliK225 [7]

Answer:

Mary is correct we don’t know the temperature but it can be implied that one is 20 and the other is -20 because of absolute value which is the distance a number away from zero that means that you have two answers or two days in this case that both have an absolute value of 20

Step-by-step explanation:

5 0
2 years ago
Suppose that a cyclist began a 476
mojhsa [17]
Well, we know the cyclist left the western part going eastwards, at the same time the car left the eastern part going westwards

the distance between them is 476 miles, and they met 8.5hrs later

let's say after 8.5hrs, the cyclist has travelled "d" miles, whilst the car has travelled the slack, or 476-d, in the same 8.5hrs

we know the rate of the car is faster... so if the cyclist rate is say "r", then the car's rate is r+33.2

thus    \bf \begin{array}{lccclll}
&distance&rate&time\\
&-----&-----&-----\\
\textit{eastbound cyclist}&d&r&8.5\\
\textit{westbound car}&476-d&r+33.2&8.5
\end{array}\\\\
-----------------------------\\\\
\begin{cases}
\boxed{d}=8.5r\\\\
476-d=(r+33.2)8.5\\
----------\\
476-\boxed{8.5r}=(r+33.2)8.5
\end{cases}

solve for "r", to see how fast the cyclist was going

what about the car? well, the car's rate is r + 33.2
6 0
3 years ago
T-shirts at a clothing store cost $19 each Rory bought several T-shirts at this price and paid $57 how many t-shirts did Rory bu
Vitek1552 [10]
One t-shirt = $19

Number of t-shirts = $57 ÷ $19 = 3

Answer: 3 t-shirts
4 0
2 years ago
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