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Alja [10]
3 years ago
5

Evaluate the expression when x = 4 and y = 3. 2[(x - 1) + 2xy] A) 31 B) 40 C) 42 D) 54 E) 492

Mathematics
2 answers:
Dennis_Churaev [7]3 years ago
7 0

When You Evaluate the expression you the Answer D) 54

jarptica [38.1K]3 years ago
5 0

D

evaluate the contents of the square bracket before multiplying by 2

substitute x = 4 and y = 3 into the expression

=2 [ (4 - 1 ) + (2 × 4 × 3 )]

= 2[3 + 24] = 2 × 27 = 54 → D



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Marina CMI [18]

Hey there! :)

Answer:

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Step-by-step explanation:

If p(x) = r(x) - c(x), subtract the two equations. Therefore:

p(x) = 10x - (4x + 15)

p(x) = 10x - 4x - 15

Combine like terms and simplify:

p(x) = 6x - 15

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lidiya [134]

Answer:

As the pvalue of the test is 0.02097 < 0.1, using a .10 significance level, he can conclude that the average trunk diameter of a pine tree is greater than the average diameter of a spruce tree.

Step-by-step explanation:

Using a .10 significance level, can he conclude that the average trunk diameter of a pine tree is greater than the average diameter of a spruce tree

The null hypothesis is that they are equal(that is, subtraction between the means is 0), while the alternate hypothesis is that they are greater(that is, subtraction between the means is larger than 0). So

H_0: \mu_1 - \mu_2 = 0

H_a: \mu_1 - \mu_2 > 0

In which \mu_1 is the mean pine trees height while \mu_2 is the mean spruce trees height.

The test statistic is:

z = \frac{X - \mu}{s}

In which X is the sample mean, \mu is the value tested at the null hypothesis and s is the standard error.

0 is tested at the null hypothesis:

This means that \mu = 0

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The sample mean is given by the subtraction of the means. So

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This means that the standard error for each sample is given by:

s_1 = \frac{\sqrt{160}}{\sqrt{40}} = 2

s_1 = \frac{\sqrt{160}}{\sqrt{80}} = \sqrt{2}

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s = \sqrt{2^2 + (\sqrt{2})^2} = \sqrt{6} = 2.4495

Test statistic:

z = \frac{X - \mu}{s}

z = \frac{5 - 0}{2.4495}

z = 2.04

Pvalue of the test:

Probability of a sample mean larger than 5, which is 1 subtracted by the pvalue of Z when X = 5.

Looking at the z-table, z = 2.04 has a pvalue of 0.9793.

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As the pvalue of the test is 0.02097 < 0.1, using a .10 significance level, he can conclude that the average trunk diameter of a pine tree is greater than the average diameter of a spruce tree.

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Answer:

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