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AleksAgata [21]
4 years ago
11

A world war ii bomber flies horizontally over level terrain, with a speed of 273 m/s relative to the ground and at an altitude o

f 3.27 km. the bombardier releases one bomb. (a) how far does the bomb travel horizontally between its
Physics
1 answer:
Alex_Xolod [135]4 years ago
6 0
Given:
u = 273 m/s, horizontal launch speed
h = 3.27 km = 3270 m, altitude.
v = 0, vertical launch speed

g = 9.8 m/s².
Wind resistance is ignored.

The time, t, for the bomb to reach the ground is given by
0t + (1/2)gt² = h
4.9t² = 3270
t² = 667.3469
t = 25.833 s

The horizontal distance traveled is
273*25.833 = 7052.4 m = 7.0524 km

Answer: 7.05 km

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Answer:

An ion.

Explanation:

Atoms can gain or lose electrons and become ions, which are atoms that have a positive or negative charge, because they have unequal numbers of protons and electrons.

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The attraction between earth and the moon is an example of ________ force. the attraction between earth and the moon is an examp
Korolek [52]

The answer is gravitational force. The gravitational force between the earth and the moon is the similar as between any other two masses in space.

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What is the relationship between gravity and electromagatism?
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3 years ago
A mountain-climber friend with a mass of 74 kg ponders the idea of attaching a helium-filled balloon to himself to effectively r
bazaltina [42]

Answer:

V=16.65 m^3

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The volume of the balloon can be find compared the force in each cases so:

reduce 25% from 74kg

R=\frac{25}{100}*74kg=18.5kg

So the net force uproad on the balloon is

F_b=18.5kg*g

Now the density of the both gases air and helium are different however the volume is the same change offcorss the mass so:

P_h=\frac{m}{V}=0.179 kg/m^3

P_A=1.29 kg/m^3

F_b=F_A-F_H

F_b=m_a*g-m_h*g

m=P/V

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4 0
3 years ago
A sample of metallic frewium weighs 185N on a spring scale in air. When immersed in pure water, the frewium pulls on the scale w
balu736 [363]

Wow !  This one could have some twists and turns in it.
Fasten your seat belt.  It's going to be a boompy ride.

-- The buoyant force is precisely the missing <em>30N</em> .

--  In order to calculate the density of the frewium sample, we need to know
its mass and its volume.  Then, density = mass/volume .

-- From the weight of the sample in air, we can closely calculate its mass.

   Weight = (mass) x (gravity)
   185N = (mass) x (9.81 m/s²)
   Mass = (185N) / (9.81 m/s²) = <u>18.858 kilograms of frewium</u> 

-- For its volume, we need to calculate the volume of the displaced water.

The buoyant force is equal to the weight of displaced water, and the
density of water is about 1 gram per cm³.  So the volume of the
displaced water (in cm³) is the same as the number of grams in it.

The weight of the displaced water is 30N, and weight = (mass) (gravity).

           30N = (mass of the displaced water) x (9.81 m/s²)

           Mass = (30N) / (9.81 m/s²) = 3.058 kilograms

           Volume of displaced water = <u>3,058 cm³</u>

Finally, density of the frewium sample = (mass)/(volume)

      Density = (18,858 grams) / (3,058 cm³) = <em>6.167 gm/cm³</em> (rounded)

================================================

I'm thinking that this must  be the hard way to do it,
because I noticed that

       (weight in air) / (buoyant force) =  185N / 30N = <u>6.1666...</u>

So apparently . . .

        (density of a sample) / (density of water) =

                                  (weight of the sample in air) / (buoyant force in water) .

I never knew that, but it's a good factoid to keep in my tool-box.


3 0
3 years ago
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