Answer:
v = 1.078 10⁴ m / s
Explanation:
To solve this exercise we can use conservation of mechanical energy
Starting point. Just clearing
Em₀ = K + U = ½ m v² - G m M / 
Final point. At r = 14R_{e}
Em_{f} = U = -G m M / 14R_{e}
how energy is conserved
Em₀ = 
½ m v² - G m M /R_{e} = -G m M / 14R_{e}
½ v² = G M / R_{e} (-1/14 + 1)
v² = 2 G M / R_{e} 13/14
we calculate
v² = 2 6.67 10⁻¹¹ 5.98 10²⁴ / 6.37 10⁶ 13/14
v = √ (1,16 10⁸)
v = 1.078 10⁴ m / s
Answer:
sure I will helpy you iru
Answer:
-5.29 m/s
Explanation:
Given:
y₀ = 1.43 m
y = 0 m
v₀ = 0 m/s
a = -9.8 m/s²
Find: v
v² = v₀² + 2a (y − y₀)
v² = (0 m/s)² + 2(-9.8 m/s²) (0 m − 1.43 m)
v = -5.29 m/s
Answer:
Explanation:
Given
initially steam is at 
and converted to 
ice
Let m be the mass of steam
latent heat of fusion and vaporization for water is
Heat required to convert steam in to water at
Heat required to lower water temperature to 
Heat required to convert water to ice at is
So this energy is equal to kinetic energy of bullet of mass m moving with velocity v
Not sure we can open those image files, but I think it would be 6.3*10^0
