Question

Help plz !!! answers??

Answer 1

Answer:

Part 1) $y=-2x-1$

Part 2) $y=-(1/2)x+(5/2)$

Step-by-step explanation:

Part 1)

we know that

If two lines are perpendicular

then

the product of their slopes is equal to minus one

so

$m1*m2=-1$

Find the slope of the given line

we have

$y=\frac{1}{2}x-1$

the slope of the given line is $m1=(1/2)$

Find the slope of the line perpendicular to the given line

$(1/2)*m2=-1$

$m2=-2$

Find the equation of the line into slope intercept form

$y=mx+b$

we have

$m=-2$

$point (-2,3)$

substitute and solve for b

$3=-2(-2)+b$

$3=4+b$

$b=-1$

The equation is equal to

$y=-2x-1$

Part 2)

we know that

If two lines are perpendicular

then

the product of their slopes is equal to minus one

so

$m1*m2=-1$

Find the slope of the given line

we have

$y+1=2(x-3)$ -----> equation of the line into point slope form

the slope of the given line is $m1=2$

Find the slope of the line perpendicular to the given line

$(2)*m2=-1$

$m2=-(1/2)$

Find the equation of the line into slope intercept form

$y=mx+b$

we have

$m=-(1/2)$

$point (5,0)$

substitute and solve for b

$0=(-1/2)(5)+b$

$b=5/2$

the equation is equal to

$y=-(1/2)x+(5/2)$