Answer:
Area of the rhombus, A = 22.5 sq. ft.
Step-by-step explanation:
The area of a rhombus = a. b
where, a = side of the rhombus
and b = height of the rhombus.
Here, the side, a = 5 ft
Height, b = 4.5 ft.
Therefore, area, A = 5 X 4.5 sq. ft
⇒ A = 22.5 sq. ft which is the required answer.
The answer is 12.8 cm³
<span>The volume ( v) of a gas in a container at a constant temperature varies inversely as the pressure (p):
v = k/p
p * v = k (k - constant)
p1v1 = k
p2v2 = k
So, p1v1 = p2v2
v1 = 24 cm</span>³
p1 = 16 lb
v2 = ?
p2 = 30 lb
24 * 16 = x * 30
384 = x * 30
x = 384 / 30
x = 12.8 cm³
Answer:
x = 0.667 and y = -0.6
Step-by-step explanation:
Given that,
6x + 5y = 1 ....(1)
6x - 5y = 7 ...(2)
We need to solve the above equations.
Subtract equations (1) and (2)
6x + 5y -(6x - 5y) = 1-7
6x+5y-6x+5y = -6
10y=-6
y = -0.6
Put the value of y in equation (1).
6x + 5(-0.6) = 1
6x = 1-5(-0.6)
6x = 4
x = 0.667
Hence, first step is to subtract equation (1) and (2) then put the value of y in equation (1).
A heptagon, unless the lines cross somewhere.
