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kiruha [24]
3 years ago
7

To determine the pH of a solution using a pH indicator paper, you need a .

Chemistry
2 answers:
bonufazy [111]3 years ago
6 0

PH is the water and it color blue

kherson [118]3 years ago
6 0

Answer:

color key

creating a color key

Have known pH values

Explanation:

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How many moles of Hions are present in the following aqueous solution?
Fittoniya [83]

Answer:

Nitric acid is a strong acid meaning it completely dissociates in water. Therefore, you can say that the concentration of H+ ions in solution is the same as the concentration of the acid (molar concentration). So once you have that, you can use the pH formula to find the pH of the acid.

pH = -log[H+]

So if you have .15 M HNO3 the pH is 0.82.

But, if you have a different concentration, the pH will change.

Explanation:

6 0
3 years ago
What do scientists use the term “light-year” to describe?
Tatiana [17]

Answer:

Astronomers measure distance in space or the distance light travels in one Earth year.

" A light-year is how astronomers measure distance in space. It's defined by how far a beam of light travels in one year – a distance of six trillion miles."

7 0
3 years ago
A laser is used in eye surgery to weld a detached retina back into place. The wavelength of the laser beam is 503 nm, while the
V125BC [204]

Answer:

Number of proton emmitted by laser=2.48*10^17proton

Explanation:

Energy is the ability to cause change; power is directly proportional to energy and its the rate energy is utilized.

Power=energy/time.

First we need to calculate the total energy used which is equal to the total power utilized.

E(total)= P( total) = 1.4W × 0.070 s =0.098J

CHECK THE ATTACHMENT FOR THE REMAINING DETAILED CALCULATION

4 0
4 years ago
Helppp pleaseee <br> How many hydrogen atoms are indicated by the formula (NH4)2C7H10O2?
Leya [2.2K]

Answer:

The correct answer is - 18.

Explanation:

The number of hydrogen atoms is indicated by the formula (NH4)2C7H10O2  that has two parts (NH4)2 and C7H10O2 then

Number of hydrogen atoms in (NH4)2 = 4*2= 8

number of H atoms in C7H10O2 = 10

then the total number of atoms = 10+8

= 18.

Thus, the correct answer is = 18 hydrogen atoms.

3 0
3 years ago
The dissociation of molecular iodine into iodine atoms is represented as i2(g) ⇌ 2i(g) at 1000 k, the equilibrium constant kc fo
ki77a [65]

First, we must write the <u>balanced chemical equation</u> for the process:

I₂ (g) ⇌ 2I (g)

The chemical reactions that occur in a closed container can reach a state of <u>chemical equilibrium</u> that is characterized because <u>the concentrations of the reactants and products remain constant over time</u>. The equilibrium constant of a chemical reaction is the value of its reaction quotient in chemical equilibrium.

<u>The equilibrium constant (Kc) is expressed as the ratio between the molar concentrations (mol/L) of reactants and products.</u> Its value in a chemical reaction <u>depends on the temperature</u>, so it must always be specified.

So, the <u>equilibrium constant </u>for the above reaction is,

Kc = \frac{[I]^{2} }{[I_{2} ]}

The initial concentration of I₂ is:

[I₂]₀ = \frac{0.0456 mol}{2.28 L} → [I₂]₀ = 0.0200 M

To facilitate the visualization of the reaction, we can write it in the following way,

        I₂        ⇌         2I

0.0200 M                -                   <em>initial</em>

0.0200 M - x          2x                 <em>equilibrium</em>

As the reaction doesn't go to completion, at equilibrium an amount <em>x</em> dissociates of the initial concentration of I₂ to produce <em>2x</em> of I  (because of the stequiometric coefficients).

At equilibrium [I₂] = 0.0200 M - x and [I] = 2x. <u>By substituting this in the above equation for kc we will be able to find the value of x and then calculate the concentrations of both gases in equilibrium.</u>

If kc = 3.80ₓ10⁻⁵ we have,

Kc = \frac{[I]^{2} }{[I_{2} ]} = \frac{(2x)^{2} }{0.0200 - x} = 3.80x10^{-5}

Since the dissociation constant has such a low value, we can assume that the degree of dissociation of I₂ is very low, therefore x ≈ 0 and,

\frac{(2x)^{2} }{0.0200 - x} = \frac{4x^{2} }{0.0200}  = 3.80x10^{-5}

→ <u>x = 4.36ₓ10⁻⁴ M</u>

Then, the concentrations of the gases I₂ and I at equilibrium are,

[I₂] = 0.0200 M - x = 0.0200 M - 4.36ₓ10⁻⁴ M →  [I₂] = 0.0196 M

[I] = 2x = 2 x 4.36ₓ10⁻⁴ M →  [I] = 8.72ₓ10⁻⁴ M

3 0
3 years ago
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