1.1 / 2 = .7 --> 2.86 yrs
.7 / 2 = .45 —> 5.72 yrs
.45 / 2 = .225 —> 8.58 yrs
.225 / 2 = .1125 —> 11.44 yrs
So, for the sample of plutonium to reach .140 mg it should take a little less than 11.44 years.
Hope this helps
Answer:
The anion of the compound is b CH3COO-
Explanation:
The compound cupric acetate Cu(CH3COO)2 undergo dissociation to form cupric ion Cu2+ and Acetate anion(CH3COO-)
Cu(CH3COO)2⇒ Cu2+ + CH3COO-
From the above equation it can be stated that the anion of Cu(CH3COO)2 is CH3COO-.
Number 1 is 4.875 Number 2 is 3.47 repeating
4.48 mol Cl2. A reaction that produces 0.35 kg of BCl3 will use 4.48 mol of Cl2.
(a) The <em>balanced chemical equation </em>is
2B + 3Cl2 → 2BCl3
(b) Convert kilograms of BCl3 to moles of BCl3
MM: B = 10.81; Cl = 35.45; BCl3 = 117.16
Moles of BCl3 = 350 g BCl3 x (1 mol BCl3/117.16 g BCl3) = 2.987 mol BCl3
(c) Use the <em>molar ratio</em> of Cl2:BCl3 to calculate the moles of Cl2.
Moles of Cl2 = 2.987 mol BCl3 x (3 mol Cl2/2 mol BCl3) = 4.48 mol Cl2
